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Blababa [14]
3 years ago
12

URGENT

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

The answer to your question is: (x² + 4x + 5)(x² + 1)  Second option

Step-by-step explanation:

                                        x² + 4x + 5

                      x² + 1         x⁴ + 4x³ + 6x² + 4x + 5

                                     -x⁴            -   x²

                                       0   + 4x³ + 5x² + 4x

                                            - 4x³            -4x

                                               0      +5x²    0   + 5

                                                        -5x²          -5

                                                         0               0

Remainder = 0

The first and the last options are not solutions because there was not remainder.

The third option is incorrect because the second term is negative and must be positive.

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