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Lostsunrise [7]
4 years ago
7

Find the values of y = r(x) = ∛x for

Mathematics
2 answers:
eduard4 years ago
8 0
We're being asked to find the values of y for \sqrt[3]{x} for specific values of x. Basically, we are taking the cube roots of these numbers.



r(-2.197) = \sqrt[3]{-2.197} = -1.3\\\\ r(-1.331) = \sqrt[3]{-1.331} = -1.1\\\\ r(0) = \sqrt[3]{0} = 0 \\\\ r(1.331) = \sqrt[3]{1.331} = 1.1\\\\r(2.197) = \sqrt[3]{2.197} = 1.3\\\\r(-3.375) = \sqrt[3]{-3.375} = 1.5\\\\r(4.913) = \sqrt[3]{4.913} = 1.7\\\\

Maslowich4 years ago
5 0

Answer:

Step-by-step explanation:

For a given function r(x) = y = ∛x

We have to fined the points on the given curve and then we will plot the points on a graph.

y = ∛x

For x = -2.197

y = ∛(-2.197) = -1.30

For x = -1.331

y = ∛(-1.331) = -1.1

For x = 0

y = ∛0 = 0

For x = 1.331

y = ∛1.331 = 1.1

For x = 2.197

y = ∛2.197 = 1.30

For x = 4.913

y =∛4.913 =1.70

So the points are (-2.197, -1.30), (-1.331, -1.1), (0, 0), (1.331, 1.1), (2.197, 1.30), (4.913, 1.70)

Now we plot the points on a graph.

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Circle A has a diameter of 9 cm Circle B has a radius of 5 cm which Circle has the largest circumference and about how many cent
Alexandra [31]

Answer:

circle b and it is bigger by 1 centimeter

Step-by-step explanation:

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4 0
4 years ago
How to rewrite the sum of 96 80 using distributive property?
elena-14-01-66 [18.8K]
96+80= (100-4)+(100-20)
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3 years ago
Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .
anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

We need to begin with the definition of tangent:

tan (x) =\frac{sin(x)}{cos(x)}

So we can replace into our formula and we got:

tan(x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

We have the following identities useful for this case:

sin(a-b) = sin(a) cos(b) - sin(b) cos(a)

cos(a-b) = cos(a) cos(b) + sin (a) sin(b)

If we apply the identities into our equation (1) we got:

tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}   (2)

Now we can divide the numerator and denominato from expression (2) by \frac{1}{cos(x) cos(y)} and we got this:

tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}

And simplifying we got:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

And this identity is satisfied for all:

(x-y) \neq \frac{\pi}{2} +n\pi

8 0
3 years ago
Please answer fast! (10 points)
SIZIF [17.4K]

Answer:

can u show me a picture of this problem.

Step-by-step explanation:

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1) solve for y.
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