The width of the card to the nearest tenth of an inch is 6.15 inches
<h3>Area of rectangle</h3>
- Width = x
- Length = 2x + 1
- Area = 88 square inches
Area of a rectangle = Length × Width
88 = (2x + 2) × x
88 = 2x² + 2x
2x² + 2x - 88 = 0
x = -b ± √b² - 4ac / 2a
= -2 ± √2² - 4(2)(-88) / 2(2)
= -2 ± √4 - (-704) / 4
= -2 ± √708 / 4
= -1/2 ± √177/2
x = 6.15 or -7.15 inches
The width of the rectangle can not be negative, so, 6.15 inches is the width.
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Are there any other symbols missing in this equation because right now it’s just the variables
Vertex = (3, - 2) this should be your answer. dm if im wrong
1500*16=24,000
16*2=32
There are 32 defective light bulbs.
-8(3 - s) = 32
So you expand the brackets
-24 + 8s = 32
And then solve
+ 24
8s = 56
÷ 8
s = 7
Hope this helps!
