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OverLord2011 [107]
3 years ago
13

For tall heterozygotes with antennae, the offspring are:

Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0

Recombinant frequency between T and A is 12%

<u>Explanation:</u>

<u></u>

Two characters are considered - height and antennae

Traits of height - Tall and Dwarf

Traits of antennae - Antennae and No antennae

<u>Given:</u>

<u />

Tall-antennae (46) and dwarf-no antennae (42) are the wild type.

Dwarf- antennae (7) and tall- no antennae (5) are the recombinants.

Total possibilities = 100

Recombinant frequency = \frac{7}{100} + \frac{5}{100}

Recombinant frequency = \frac{12}{100}

Recombinant frequency in percentage = \frac{12}{100} X 100 = 12%

Therefore, recombinant frequency between T and A is 12%

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3 years ago
0.58 x 3 =<br> 1.74<br> Explain how you solved the problem?? <br><br> Any help
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