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zheka24 [161]
3 years ago
8

Find the equation of a line that contains the points (-2,-3 and. (0,4). Express the equation in a slope-intercept form.

Mathematics
2 answers:
lys-0071 [83]3 years ago
5 0
--------------------------------------
Find Slope :
--------------------------------------
\text { Slope = }  \dfrac{4+3}{0+2} =  \dfrac{7}{2}

--------------------------------------
Find y-intercept
--------------------------------------
At (0, 4), y-intercept = 4

--------------------------------------
Equation :
--------------------------------------
y = mx + b

y =  \dfrac{7}{2} x + 4



julia-pushkina [17]3 years ago
4 0
Hey there!

Slope intercept form is defined as:

y = mx + b

Where m is the slope and b is the y intercept.

In order to find the slope, we can use the slope given two points formula:

y2-y1/x2-x1 = 4-(-3)/0-(-2) = 4 + 3/2 = 7/2

Now, we can plug in the x and y values, as well as the slope to find b. We'll use (-2, -3). We have:

-3 = 7/2(-2) + b
-3 = -14/2 + b
-3 = -7 + b
-3 + 7 = b
4 = b

Our equation is y = 7/2x + 4

Hope this helps!


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