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notsponge [240]
3 years ago
7

Write the following inequality in slope-intercept form. 5x – 5y ≥ 70

Mathematics
2 answers:
White raven [17]3 years ago
4 0
5x - 5y >= 70
Move the 5x to the right by subtracting 5x from both sides
- 5y >= -5x + 70
Divide both sides by -5 and when you divide by a negative you have to change the inequality sign.
y <= x - 14 Letter B
spin [16.1K]3 years ago
4 0
I am pretty sure its B
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Pls help stuck on big ideas math
beks73 [17]

Answer:

x = 15

Step-by-step explanation:

Substitute: -4/5x + 7 = -5

Rearrange unknown terms to the left side of the equation: -4/5x = -5 - 7

Calculate the sum or difference: -4/5x = -12

Divide both sides of the equation by the coefficient of variable: x = -12 × (-5/4)

Remove the parentheses: x = 12 × 5/4

Cross out the common factor: x = 3 × 5

Calculate the product or quotient: x = 15

So the answer is: x = 15

3 0
2 years ago
In angle PQR, angle P = (4x – 14)º, angle Q = (5x + 6)", and angle R= (x - 2)°. Find<br> angle R.
vekshin1

we have: ∠P + ∠Q + ∠R = 180°

<=> (4x – 14)º + (5x + 6)° + (x - 2)° = 180°

<=> 4x – 14 + 5x + 6 + x - 2 = 180°

<=> 10x - 10 = 180°

<=> 10x = 190

<=> x = 19°

So: ∠R = (x - 2)° = (19 - 2)° = 17°

ok done. Thank to me :>

5 0
2 years ago
What is the slope of the equation: x = -2
Harrizon [31]

Answer:

undefined

Step-by-step explanation

it is a vertical line and has no defined slope

5 0
3 years ago
Class Election Results
ki77a [65]

Answer:

not me doing this 4 points:00

Step-by-step explanation:

sry. :

3 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
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