All categories

3 years ago

Write the following inequality in slope-intercept form. 5x – 5y ≥ 70

2 answers:

4 0

5x - 5y >= 70
Move the 5x to the right by subtracting 5x from both sides
- 5y >= -5x + 70
Divide both sides by -5 and when you divide by a negative you have to change the inequality sign.
y <= x - 14 Letter B

spin [16.1K]3 years ago

4 0

I am pretty sure its B

You might be interested in

Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

413,125 round to nearest hundred thousand

NARA [144]

413,125 rounded to the nearest hundred thousand is 400,000

8 0

3 years ago

20. Carmen can buy bottles of paint for $2.00 each and boxes of colored pencils for $3.50 each. She can spend no more than

KIM [24]

Answer:

(5, 8), (7, 1), (15, 3)

Step-by-step explanation:

a) The variables are defined in the problem statement. The total expenditure must satisfy ...

2.00x +3.50y ≤ 42.00

b) Possible solutions include ...

(x, y) ∈ {(5, 8), (7, 1), (15, 3)}

These were chosen by looking at the attached graph of the equation.

6 0

3 years ago

175 pages in 5 days = __ pages in 2 days

barxatty [35]

In 5 days, = 175 pages
so, in 1 day = 175/5 Pages

Now, In 2 days, it would be: 175/5 * 2 = 35 * 2 = 70

So, your final answer is 70

Hope this helps!

8 0

3 years ago

Read 2 more answers

I need help with this please

harina [27]

Answer:

acute

Step-by-step explanation:q

7 0

3 years ago

Read 2 more answers