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Answer:
even if it all could be used, it wouldn't be enough
Explanation:
The land area of the US is about 5.45% of the world's area, so the amount of released heat over the area of the US is on the order of 2.4 Tw. Current technology for converting geothermal energy to electricity is about 12% efficient, so the available energy might amount to 0.29 Tw if it could all be captured.
Energy consumption in the US in 2019 was on the order of 0.46 Tw. This suggests that even if <em>all</em> of the thermal energy radiated by the Earth from the US could be turned to useful forms of energy, it would meet only about 60% of the US need for energy.
Answer:
<u>Frequency</u>- number of wave cycles that occur in a given amount of time.
<u>Pitch</u>- number of wavelengths in a given amount of time.
<u>Amplitude</u>- fluctuation or displacement of a wave from its mean value. That means how high or low they are away from the center line.
<u>Volume</u>- The perception of loudness from the intensity of a sound wave. The higher the intensity of a sound, the louder it is perceived in our ears, and the higher volume it has.
<u>Wavelength</u>- the distance between the tops of the "waves".
It's difficult to measure that because it's hard to make sure it is only a uniform layer of gas in whatever you're measuring it in
Answer:
Density of rock will be equal to 
Explanation:
It is given that mass of the rock 
Volume displaced bu rock 
We have to find the density of rock
Density is equal to ratio of mass and volume
Therefore density of rock 

So density of rock will be equal to 