Answer:
Speed of first car= 48 mph
Speed of second car= 32 mph
Explanation:
From the question, the following parameters are given
Distance travelled by the first car (d1) =224 miles
Distance travelled by the second car (d2)= 160 miles (it is obvious the second car is not as fast as the first car) since both cars attain these distances at the same time.
Time for the first car to attain 224 miles (t1)
Time for the second car to attain 160miles (t2). From the question, t1=t2.......(i)
Speed of the first car is 16mph faster than the second car. Then speed of first car
(s1 =s2+16)......(ii)
Where s1 is speed of first car and s2 is speed of second car.
Speed=distance/time travelled
For the first car, s1=d1/t1....(iii)
Substituting (ii) and d1=224 miles into (iii), we have
s2+16=224/t1
Making t1 the subject of the formular
t1=244/(s2+16).....(iv)
For the second car, s2=d2/t2...(v)
Substituting d2=160 miles into (v),
We have
s2=160/t2
Making t2 the subject of the formular
t2=160/s2....(vi)
Since t1=t2, we can equate (iv) and (vi) to become
224/(s2+16)=160/s2
By cross multiplying, you have
224s2=160s2+2560
You will obtain s2=32mph when you solve the equation above.
Since s1=s2+16
s1=32+16=48mph
- its the result