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3 years ago

The u.s has sent unmanned spacecrafts to ___ the planets in our solar system

2 answers:

6 0

I think it's C. if we're talking about a rover.

But if it's a rocket that's computerized and automatic (synonym of unmanned)... Then it's B.

Dima020 [189]3 years ago

4 0

I think the answer is A.

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There is a parallel plate capacitor. Both plates are 4x2 cm and are 10 cm apart. The top plate has surface charge density of 10C

liberstina [14]

Answer:

1) The total charge of the top plate is 0.008 C

b) The total charge of the bottom plate is -0.008 C

2) The electric field at the point exactly midway between the plates is 0

3) The electric field between plates is approximately 1.1294 × 10¹² N/C

4) The force on an electron in the middle of the two plates is approximately 1.807 × 10⁻⁷ N

Explanation:

The given parameters of the parallel plate capacitor are;

The dimensions of the plates = 4 × 2 cm

The distance between the plates = 10 cm

The surface charge density of the top plate, σ₁ = 10 C/m²

The surface charge density of the bottom plate, σ₂ = -10 C/m²

The surface area, A = 0.04 m × 0.02 m = 0.0008 m²

1) The total charge of the top plate, Q = σ₁ × A = 0.0008 m² × 10 C/m² = 0.008 C

b) The total charge of the bottom plate, Q = σ₂ × A = 0.0008 m² × -10 C/m² = -0.008 C

2) The electrical field at the point exactly midway between the plates is given as follows;

$V_{tot} = V_{q1} + V_{q2}$

$V_q = \dfrac{k \cdot q}{r}$

Therefore, we have;

The distance to the midpoint between the two plates = 10 cm/2 = 5 cm = 0.05 m

$V_{tot} = \dfrac{k \cdot q}{0.05} + \dfrac{k \cdot (-q)}{0.05} = \dfrac{k \cdot q}{0.05} - \dfrac{k \cdot q}{0.05} = 0$

The electric field at the point exactly midway between the plates, $V_{tot}$ = 0

3) The electric field, 'E', between plates is given as follows;

$E =\dfrac{\sigma }{\epsilon_0 } = \dfrac{10 \ C/m^2}{8.854 \times 10^{-12} \ C^2/(N\cdot m^2)} \approx 1.1294 \times 10^{12}\ N/C$

E ≈ 1.1294 × 10¹² N/C

The electric field between plates, E ≈ 1.1294 × 10¹² N/C

4) The force on an electron in the middle of the two plates

The charge on an electron, e = -1.6 × 10⁻¹⁹ C

The force on an electron in the middle of the two plates, $F_e$ = E × e

∴ $F_e$ = 1.1294 × 10¹² N/C × -1.6 × 10⁻¹⁹ C ≈ 1.807 × 10⁻⁷ N

The force on an electron in the middle of the two plates, $F_e$ ≈ 1.807 × 10⁻⁷ N

4 0

3 years ago

A crate is sitting in the center of a flatbed truck. As the truck accelerates to the east, the crate moves with it, not sliding

ozzi

Answer:

4. To the east

Explanation:

Friction forces always act in the opposite direction that an object tends to move in. In this case, when the truck accelerates to the east, the crate tends to move to the west due to inertia (the tendency for an object to remain at rest or at constant speed). In order to stop the crate from moving, there needs to be a friction force to the east.

3 0

4 years ago

Renald completed only one trial of his experiment. what effect will this most likely have?

Tatiana [17]

Remember the rule of thumb that every person learns in Elementary Science? You must do multiple experiments in order to get to a conclusion. In order for a conclusion to be valid you must test the conclusion multiple times. You wouldn't want a doctor to just test an aspirin 1 time on 1 patient and say yes it works correct? No, you would want him/her to test on multiple patients in multiple settings and conditions so that when you take an aspirin you know that it will work for what you are taking it for. So ..... with all that being said.....Your answer is (A). The results are more likely to have errors.

6 0

3 years ago

How to find gravitational force

Aleksandr [31]

The mathematical formula for gravitational force is F=GMmr2 F = G Mm r 2 where G is the gravitational constant.

3 0

4 years ago

Read 2 more answers

How are step-up transformers used in the transmission of electrical energy

bekas [8.4K]

Step-up transformers are used at power stations to produce the very high voltages needed to transmit electricity through the National Grid power lines. These high voltages are too dangerous to use in the home, so step-down transformers areused locally to reduce the voltage to safe levels.

5 0

4 years ago