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vladimir1956 [14]
3 years ago
7

Science 8 - Electromagnetic Spectrum Worksheet

Physics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

1. Electromagnetic spectrum

2. Electromagnetic radiation

3. Radiant energy

4. Infared  waves

5. Electricmagnetic radiation or Infared waves

6. Radio waves

7. Gamma rays

8. Radio waves

9. Ultraviolet rays

10. This is because it doesn’t contain water or a substance.

11. You should use sunscree and a hat to protect your skin from UV light that might  cause skin cancer.

Hope this helps

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Can someone help with these
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6.  0N.  This questions requires understanding of how friction functions.  Friction is a resistive force, meaning it opposes the direction of any applied or unbalanced forces.  The box in the question experiences no horizontal force, so there is no resistive force in response to it, making it 0N.


7.  This question tests your understanding of static friction.  Static friction only applies when an applied or unbalanced force is applied to an object which does not move.  The static friction always equals the magnitude of the applied or unbalanced force component parallel to the surface which the object rests on.  The question states that the crate starts to move only when the applied force exceeds 313N, so we use this value to determine the force of static friction.  The additional info in the question pertaining to when the crate is moving is irrelevant when determining static friction (only relevant if determining kinetic friction).  Knowing this we solve for the weight of the crate:

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4 0
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Find the center of mass (in cm) of a one-meter long rod, made of 50 cm of copper (density 8.92 g/cm3) and 50 cm of iron (density
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Answer

given,

copper rod length = 50 cm

density of the copper = 8.92 g/cm³

iron rod length = 50 cm

density of iron = 7.86 g/cm³

mass of iron = density × volume

               m_i = 7.86 × A × l/2

               m_c = 8.96 × A × l/2

taking  the intersection of copper and iron rod be starting point cooper side is taken as positive side and iron side length is taken to be  -ve side.

center of mass

 = \dfrac{m_i\times \dfrac{-l}{4}+m_c\times \dfrac{l}{4}}{m_i+m_c}

 = \dfrac{7.86\times A \times \dfrac{l}{2}\times \dfrac{-l}{4}+8.96\times A \times \dfrac{l}{2}\times \dfrac{l}{4}}{7.86\times A \times \dfrac{l}{2}+8.96\times A \times \dfrac{l}{2}}

 = \dfrac{7.86\times \dfrac{-l}{4}+8.92\times \dfrac{l}{4}}{7.86+8.92}

 = \dfrac{1.06\dfrac{l}{4}}{16.78}

 = 0.015793 m

 = 1.579 m (+ve)

center of mass shift to cooper because cooper is heavy.

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