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Kryger [21]
3 years ago
14

The yearbook staff at Jefferson Middle School has been busy taking pictures. Of the 574 pictures the staff members have taken, o

nly 246 of the pictures will make it into the yearbook. Approximately what portion of the pictures that were taken will make it into the yearbook? Use a complete portions web to show your answer. Show your work.
Mathematics
1 answer:
Fiesta28 [93]3 years ago
6 0
246/574 = 0.427 of the pictures will make it to the yearbook
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Find the equation of the linear function represented by the table below<br> in slope-intercept form.
Arturiano [62]

Answer:

Equation of a line, y = mx+c

Slope (m)= (Y2-Y1)/(X2-X1), let Y2=7, Y1=3 , X2=2 and X1=1

m=(7-3)/(2-1)

= 4/1

= 4

Picking any value of y and its corresponding x including m, put them into the equation of the line

y=mx+c

3 =4(1)+c

3=4+c

3-4=c

-1=c

y=mx+c

y=4x+(-1)

y=4x-1

8 0
2 years ago
A company rents water tanks shaped like cylinders. Each tank has a radius of 3 feet and a height of 2 feet. The cost is $4 per c
vivado [14]

Answer:

Cost to rent one tank=226.08 Dollars

Step-by-step explanation:

Radius of the cylindrical tank=3 feet

Height of the tank= 2 feet

Cost to rent one tank= Volume of one tank * cost to rent one cubic feet of volume

Volume of the cylindrical tank:

                                         =\pi r^2

As,  \pi =\frac{22}{7}=3.14

Putting the values in the formula:

Volume of the tank:

                                    =3.14*(3*3)*2\\\\=3.14*9*2\\\\=3.14*18\\\\=56.52feet^3

Cost to rent one cubic feet= 4 Dollars

Cost to rent 56.52 Cubic feet of one tank;

   = 4*56.52

=226.08 Dollars

5 0
3 years ago
rank has a circular garden. The area of the garden is 100 ft2. What is the approximate distance from the edge of Frank’s garden
Ray Of Light [21]

It is given that the area of the circular garden = 100 ft^2

Area of circle with radius 'r' = \pi r^2

We have to determine the approximate distance from the edge of Frank’s garden to the center of the garden, that means we have to determine the radius of the circular garden.

Since, area of circular garden = 100

\pi r^2 = 100

\frac{22}{7} \times r^2 = 100

r^2 = \frac{700}{22}

r^2 = 31.8

r = \sqrt{31.8}

So, r = 5.6 ft

r = 6 ft (approximately)

Therefore, the approximate distance from the edge of Frank’s garden to the center of the garden is 6 ft.

So, Option A is the correct answer.

7 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST IF ANSWERED NOW
iren [92.7K]

Answer:

y=3x-7

Step-by-step explanation:

lines are parallel hence gradient from the equation in question is the same as the gradient of the equation to be found.. comparing to y=mx+c, eq in question has grad 3... from the formula y-y1=m(x-x1) where (x1,y1) is equal to the point in question

5 0
3 years ago
Find the product.<br><br>(0.5n 5)2(10n 7) 3
sergejj [24]
Your product would be
(0.5n5)2(10n7)3
7 0
3 years ago
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