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3 years ago

For all functions of the form f(x) = ax2 + bx + c, which is true when b = 0?

2 answers:

Klio2033 [76]3 years ago

7 0

When b=0
f(x)=ax^2+c

test each
A. with x^2-1, A is false
B. with -x^2-1, B is false
C. cannot find contradiction
D. the axis is actually x=0, 0 is nithere positive nor negative, false

answer is C

tatuchka [14]3 years ago

5 0

Answer:

Step-by-step explanation:

they guy answered it

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Which graph represents a proportional relationship?

Vadim26 [7]

Answer:

The one shown in the photo

Step-by-step explanation:

A proportional relationship is one in which the relationship increases steadily, which looks like a straight line when graphed. Also, the line should pass through the <em>origin</em>, which is the point (0, 0) on a graph.

The graph shown increases steadily (it's a straight line), and passes through the origin (point 0,0) as well. So, it's proportional. Hopefully that's helpful! :)

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3 years ago

Which equation represents the graph of the linear function?

blsea [12.9K]

I think the answer is D

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3 years ago

PLZ ANSWER 6 AND 7. SHOW YOUR WORK TOO!!

anygoal [31]

6) subtract 16 on both sides

then it should be x/4>18

then you would times 18 by 4 and get

c as the answer

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3 years ago

Read 2 more answers

Line s has an equation of y=1/3-X-5. Line t is perpendicular to line s and passes through (-2, 9). What is the equation of line

anyanavicka [17]

Answer:

y = 3x + 15

Step-by-step explanation:

1. Find the reciprocal of the slope and change signs: -3

2. y = 3x + b

3. Plug in x and y --> b = 15

4. Make your equation using y = mx + b: y = 3x + 15

6 0

2 years ago

Read 2 more answers

Without actual division prove that x4 +2x3 -2x2 +2x -3 is exactly divisible by<br> x2 +2x-3

Brut [27]

Answer:

Step-by-step explanation:

$\displaystyle\Large\boldsymbol{} x^4+2x^3-2x^2+2x-3= \\\\\\x^4+2x^2(x-1)+2x-\underbrace{2-1}_{-3}= \\\\\\x^4-1+2x^2(x-1)+2x-2 = \\\\\\(x^2-1)(x^2+1)+2x^2(x-1)+2(x-1) = \\\\\\\underline{(x-1)}(x+1)(x^2+1)+2x^2\underline{(x-1)} +2\underline{(x-1)} =\\\\\\(x-1)((x+1)(x^2+1)+2x^2+2)=\\\\\\(x-1)(x^3+x^2+2x^2+x+2+1)=\\\\\\(x-1)(x^3+3x^2+x+3) =\\\\\\(x-1)( \underline{(x+3)}x^2+\underline{(x+3)})=(x^2+1)\underbrace{(x-1)(x+3)}_{x^2+2x-3}= \\\\\\(x^2+1)(x^2+2x-3) : (x^2+2x-3)=x^2+1$

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3 years ago