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Rom4ik [11]
3 years ago
14

Rainbow bread company delivered a total of 180 loaves of bread to three markets. Savemart received 12 more loaves than vons. Ral

ph's received 6 more loaves than savemart. Find the number of loaves delivered to each market
Mathematics
1 answer:
sasho [114]3 years ago
8 0

Let vons market receive x  loaves. Then savemart received x+12 loaves and Ralphs received x + 12 + 6 = x + 18 loaves, Therefore:-

x + x + 12 + x + 18 = 180

3x + 30 = 180

3x = 150

x = 150/3 = 50  

So vons received 50, savemart received 62 and ralph's received 68 loves.  Answer


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Which division fact corresponds to the problem of 8×9 equals 72
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Basically just do the problem backwards.
72÷9=8
72÷8=9
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What is prime factorization?
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In J, K is the midpoint. The coordinates of ) are (2, 2), and the coordinates of Kare (10, 11). What are the coordinates of L?
DiKsa [7]

Answer:

L(18, 20)

Step-by-step explanation:

In JL, K is the midpoint. The coordinates of J are (2, 2), and the

coordinates of K are (10, 11). What are the coordinates of L?

Solution:

If O(x, y) is the midpoint between two points A(x_1,y_1) and B(x_2,y_2). The equation to determine the location of O is given by:

x=\frac{x_1+x_2}{2} \\\\y=\frac{y_1+y_2}{2}

Since JL is a line segment and K is the midpoint. Given the location of J as (2, 2) and K as (10, 11). Let (x_2,y_2) be the coordinate of L. Therefore:

10=\frac{2+x_2}{2} \\\\20=2+x_2\\\\x_2=18

11=\frac{2+y_2}{2} \\\\22=2+y_2\\\\y_2=20

Therefore L = (18, 20)

4 0
3 years ago
Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th
STatiana [176]

We can find the acceleration via

{v_f}^2-{v_i}^2=2a\Delta x

We have

\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)

\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}

Then by definition of average acceleration,

a_{\rm ave}=\dfrac{v_f-v_i}t

so that

-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t

\implies\boxed{t=6.33\,\mathrm s}

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2

Then

\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2

\implies\boxed{t=6.33\,\mathrm s}

7 0
3 years ago
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