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blsea [12.9K]
3 years ago
13

(GIVING BRAINLIEST!!!!!!!!!)

Mathematics
1 answer:
malfutka [58]3 years ago
3 0

Answer:

0

Step-by-step explanation:

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The length of a rectangle is twice its width.
goldfiish [28.3K]
P = 2l + 2w
l = 2w

48 = 2(2w) + 2w
48 = 4w + 2w
48 = 6w
8 = w

l = 2w
l = 2(8)
l = 16

48 = 2(16) + 2(8)
48 = 32 + 16
48 = 48

Answer:
length = 16
width = 8
8 0
4 years ago
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Solve this and get 12 points
Pachacha [2.7K]

Answer:

9

Step-by-step explanation:

First, find <em>x</em>. Since <em>x</em> is the average of the three number, add the three up and then divided by three. Thus:

x=\frac{13+-16+6}{3}=3/3=1

<em>y</em> is the cube root of 8. Thus:

y=\sqrt[3]{8}=2

So:

x^2+y^3\\=(1)^2+(2)^3\\=1+8=9

5 0
3 years ago
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You start at (5,3) you move down 4 units and up 6 units. where do you end?
Anestetic [448]

You end up at the point (5, 5).

7 0
3 years ago
Find the distance between the points (0,-9) and(4,-6)
Len [333]

Answer:

d=5

Step-by-step explanation:

1. use the distance formula: d=\sqrt{(x_{2} - x_{2} )^{2} +(y_{2} -y_{1} )^{2}

2. plug in the points: d=\sqrt{(0-4)^{2} +(-9+6)^{2}

3. solve problem inside parentheses: d=\sqrt{(-4)^{2} +(-3)^{2}

4. square -4 and -3: d=\sqrt{16+9

5. add:d=\sqrt{25

6. find square root: d=5

8 0
4 years ago
You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point.
Andreyy89

Answer:

a = 9\\b = 48\\c = -1

Step-by-step explanation:

We know that:

In a deck of 52 cards there are 4 aces.

Therefore the probability of obtaining an ace is:

P (x) = 4/52

The probability of not getting an ace is:

P ('x) = 1-4 / 52

P ('x) = 48/52

In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.

For a discrete random variable V, the expected value is defined as:

E(V) = VP(V)

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.

We have the following equation for the expected value:

E(V) = \frac{4}{52}(a) + \frac{b}{52}(c)

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52

Therefore, expected value for V, the number of points obtained in the game is:

E(V) = \frac{4}{52}(9) + \frac{48}{52}(-1)

So:

a = 9\\b = 48\\c = -1

3 0
3 years ago
Read 2 more answers
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