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guajiro [1.7K]
3 years ago
11

Judy’s measured potassium level varies according to the Normal distribution with μ = 3.8 and σ = 0.2 mmol/l. Let us consider wha

t could happen if we took four separate measurements from Judy.
What is the blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L? Hint: This requires an inverse Normal calculation. (Enter you answer rounded to two decimal places.)
Mathematics
2 answers:
Basile [38]3 years ago
8 0

Answer:

The blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L is 3.64.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means of size n can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 3.8, \sigma = 0.2, n = 4, s = \frac{0.2}{\sqrt{4}} = 0.1

What is the blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L?

This is the value of X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.645 = \frac{X - 3.8}{0.1}

X - 3.8 = -1.645*0.1

X = 3.64

The blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L is 3.64.

Llana [10]3 years ago
6 0

Answer:

Blood potassium level L = 3.64

Step-by-step explanation:

We are given that Judy’s measured potassium level varies according to the Normal distribution with μ = 3.8 and σ = 0.2 mm .

Let X bar = average of four measurements

So, X bar ~ N(\mu = 3.8,\sigma = 0.2)

The z score probability distribution of sample mean is ;

            Z = \frac{Xbar -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, n = sample size = 4

           \mu = population mean = 3.8

           \sigma = population standard deviation = 0.2

The condition given to us is that probability that the average of four measurements is less than L is only 0.05 , i.e.;

 P(X bar < L) = 0.05

 P( \frac{Xbar -\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{L -3.8}{\frac{0.2}{\sqrt{4} } } ) = 0.05

 P(Z < \frac{L -3.8}{0.1 } ) = 0.05

In z table, we find that the critical value below which the z probability is 0.05 is given as -1.6449 .

So, it means;   \frac{L -3.8}{0.1 } = -1.6449

                         L = (-1.6449 * 0.1) + 3.8  

                         L = -0.16449 + 3.8 = 3.64

Therefore, the blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L is 3.64 .

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