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Art [367]
3 years ago
10

Simplify the expression by using a Double-Angle Formula or a Half-Angle Formula.

F2%29%2Acos%28x%2F2%29" id="TexFormula1" title="2*sin(x/2)*cos(x/2)" alt="2*sin(x/2)*cos(x/2)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

2\sin{\frac{x}{2}}\cos{\frac{x}{2}} = \sin{x}

Step-by-step explanation:

The double angle formula states that:

\sin{2a} = 2\sin{a}\cos{a}

In this question:

2\sin{\frac{x}{2}}\cos{\frac{x}{2}}

So

a = \frac{x}{2}

Then

2\sin{\frac{x}{2}}\cos{\frac{x}{2}} = \sin{\frac{2x}{2}} = \sin{x}

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According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are re
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Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

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