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Art [367]
3 years ago
10

Simplify the expression by using a Double-Angle Formula or a Half-Angle Formula.

F2%29%2Acos%28x%2F2%29" id="TexFormula1" title="2*sin(x/2)*cos(x/2)" alt="2*sin(x/2)*cos(x/2)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

2\sin{\frac{x}{2}}\cos{\frac{x}{2}} = \sin{x}

Step-by-step explanation:

The double angle formula states that:

\sin{2a} = 2\sin{a}\cos{a}

In this question:

2\sin{\frac{x}{2}}\cos{\frac{x}{2}}

So

a = \frac{x}{2}

Then

2\sin{\frac{x}{2}}\cos{\frac{x}{2}} = \sin{\frac{2x}{2}} = \sin{x}

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Six lines are drawn in the coordinate plane below.
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Answer:

PQ

SR

PR

Step-by-step explanation:

they are all going down while the others rise

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3 years ago
PLZ HELP I AM GONNA FAIL JUST EXPLAIN WHAT TO DO ​
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A number cube is a die (singular for dice). List all of the possible outcomes of a die (list numbers of 1 to 6), and next to those numbers, determine if they are even or odd.
8 0
3 years ago
If p:q=2/3:3 and p:r=3/4:2/3 calculate the ratio p:q:r. Giving the answer in its simplest form
adelina 88 [10]

Answer:

Given  

if p:q=2/3:3 and p:r=3/4:1/2, calculate the ratio p:q:r giving your answer in its simplest form

We need to find the ratio p:q:r

Given p:q = 2/3 : 3 = 2/3 / 3  = 2/9

and p : r = 3/4 : 1/2 = 3/4 / 1/2  = 3/2  

Now p/q = 2/9 and p/r = 3/2

We need to make p equal numerators so we get

p/q = 2/9 x 3/3 = 6/27 and

p/r = 2/3 x 3/2 = 6/4

Therefore p : q : r = 6 : 27 : 4

6 0
4 years ago
Evaluate the following limit:
Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

        \large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

<h3>Way 1:</h3>

By comparison of infinities:

We first expand the binomial squared, so we get

                         \large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

<h3>Way 2</h3>

Dividing numerator and denominator by the term of highest degree:

                            \large\displaystyle\text{$\begin{gathered}\sf L  = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4  }{x^{3}-5  }  \end{gathered}$}\\

                                \ \  = \lim_{x \to \infty\frac{\frac{x^{4}  }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} }    }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}}   }  }

                                \large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} }  }{\frac{1}{x}-\frac{5}{x^{4} }  }  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0
2 years ago
How do I subtract 45 1/3 - 9 3/5​
Basile [38]

Answer:

35.733

Step-by-step explanation:

have a common denominator then do the math

3 0
3 years ago
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