The goat is tied in the four corners of an 8-foot by 4-foot pump house. The rope is 8 feet. The goat is eating the grass, forming a circle The pattern is 3/4 of a circle radius 8 and 1/4 of a circle radius 4.
Getting the area of radius of 8 feet
Area = pi * r^2
Area = pi * 8^2
Area = 201.06 feet^2
Getting the area of radius of 4 feet
Area = pi * r^2
Area = pi * 4^2
<span>Area = 50.27 feet^2
</span>
3/4 of 201.06 = 150.80 feet ^2
1/4 of 50.27 = 12.60 feet^2
So the total area is 153.40 feet^2
Answer:
No
Step-by-step explanation:
We can use the Pytaghorean theorem to verify it
4.4^2 + 5.5^2 = 6.6^2
19.36 + 30.25 = 43.56
49.61 = 43.56 (false)
Let's go ahead and construct an equation to show this. Together, they have 50 goldfish. This can be represented as =50.
Since we don't know how many Todd has, we're going to make a variable. We'll name it T, for Todd.
What about Andres? How many does he have? 10 more than Todd. Well, if Todd's amount is T, and Andres has 10 more, we can express that as T+10.
Now, just put the two pieces together! T+10=50.
The next step is inverse operations. You want to find out how many T is, so you need to get rid of the 10. To take 10 away from something is doing what? Subtraction! Be warned, though; whatever you do to one side of the problem, you have to do to the other. 10-10 is 0, and 50-10 is 40. Since we took the 10 away and 50 is now 40, what you're left with is T=40.
Wait a second.. wasn't "T" Todd's amount? Yep! That means that Todd has 40 goldfish. And we already know that Andres has 10, so there's your answer!
I think it’s the second one
Answer:
The complete question in the graphic
A.
After synchronized exercise, it was observed that the average proximity rate has increased, which shows that the mean of the variable is positive and there is high synchronization in the groups.
.
B.
If groups with low synchronization and high effort are compared, the result of the average will be positive, so the average proximity rate will also increase after the synchronization exercise is performed.
On the contrary, if we observe the groups that have low synchronization and low effort, the mean of the variable is negative, thus the average proximity rate after performing the exercise will decrease.
(C)
considering that the total degrees of freedom is 259, it will show 260 students in the analysis.
D.
With a significance level of 5% or 0.05, the P value is less than the significance level, which leads to differentiating the mean of the scores before and after performing the combinations.
E.
With a significance level of 1% or 0.01, the p-value is higher than the significance level. With this data we can conclude that there is no difference between the results before and after the synchronized exercise
