<em>Answer: A solution to a system of equations means the point must work in both equations in the system. So, we test the point in both equations. It must be a solution for both to be a solution to the system. Hope this helps.</em>
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<em>I hope it helps if it does can please mark me as Brainliest thank you!</em>
Hiya. I'm going to rewrite the second equation.
By subtracting 5x by both sides, I'll be able to have y by itself:
-y=-5x+13
I'm going to then divide both sides by -1 to get:
y=5x-13.
Then, I'm going to plug that equation into the first equation
3x+2(5x-13)=39
Factor:
3x+10x-26=39
Combine like terms:
13x=65
Divide both sides by 13 to get x by itself to get x=5
Plug this back into the equation of y=5x-13
y=5(5)-13 to get y=12
Answer:

Step-by-step explanation:
Using the rules of exponents
×
=
,
=
,
= 
Simplifying the product of the first 2 terms
× 
=
× 
= 
Simplifying the third term
5(
= 5
= 5
Performing the division, that is
← cancel
on numerator/ denominator leaves
= 
Answer:
B is correct.
Step-by-step explanation:
Quadratic Expression (Standard Form) is:

To say it simply, the expression must have 2 as the highest degree.
This means that if there are any higher or lower degrees than 2 then they are not quadratic expression.
A choice is not quadratic expression because it has 1 as the highest degree.
B choice is correct because 2 is the highest degree.
C choice is wrong because 3 is the highest degree.
D choice is wrong because it is not a polynomial.
Therefore, B is correct.