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Softa [21]
2 years ago
12

Which of these ordered pairs is a solution to the linear inequality y – 3x ≤ –8?

Mathematics
2 answers:
marysya [2.9K]2 years ago
6 0
C is correct. (1,-5)

-5 - 3(1) =
-5 + - 3 = -8

Kobotan [32]2 years ago
5 0

Answer:

C. (1, -5)

Step-by-step explanation:

If the ordered pair is a solution to the system, then it must satisfy the equation.

The given linear inequality is,

y-3x \leq -8

A. (-2, 4)

\Rightarrow 4-3(-2) \leq -8

\Rightarrow 4+6 \leq -8

\Rightarrow 10\nless -8

So it is not the solution to the system.

B. (1, 3)

\Rightarrow 3-3(1) \leq -8

\Rightarrow 3-3 \leq -8

\Rightarrow 0\nless -8

So it is not the solution to the system.

C. (1, -5)

\Rightarrow -5-3(1) \leq -8

\Rightarrow -5-3 \leq -8

\Rightarrow -8\leq -8

As it satisfies the equation, so it is the solution of the system.

D. (3, 4)

\Rightarrow 4-3(3) \leq -8

\Rightarrow 4-9 \leq -8

\Rightarrow -5\nless -8

So it is not the solution to the system.

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What is (8n^2-26n+20) divided by (n-2)?
Mama L [17]

Answer:

A. 8n-10

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7 0
3 years ago
Ionizing radiation is being given increasing attention as a method for preserving horticultural products. A study reports that 1
kolbaska11 [484]

Answer:

Yes, there is  enough evidence to support the claim that ionizing radiation is beneficial in terms of marketability.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that ionizing radiation is beneficial in terms of marketability.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

Being π1: the true proportion of treated bulbs that can be comercialized after 240 days, and π2: the true proportion of untreated bulbs that can be comercialized after 240 days.

The significance level is 0.05.

The sample 1, of size n1=180 has a proportion of p1=0.85.

p_1=X_1/n_1=153/180=0.85

The sample 2, of size n2=180 has a proportion of p2=0.65.

p_2=X_2/n_2=117/180=0.65

The difference between proportions is (p1-p2)=0.2.

p_d=p_1-p_2=0.85-0.65=0.2

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{153+117}{180+180}=\dfrac{270}{360}=0.75

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.75*0.25}{180}+\dfrac{0.75*0.25}{180}}\\\\\\s_{M_d}=\sqrt{0.001+0.001}=\sqrt{0.002}=0.0456

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.2-0}{0.0456}=\dfrac{0.2}{0.0456}=4.382

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t>4.382)=0.000008

As the P-value (0.000008) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that ionizing radiation is beneficial in terms of marketability.

7 0
3 years ago
Last question for today:<br><br>-4/7en - 3/7en = ?
Illusion [34]

-\dfrac{4}{7}en-\dfrac{3}{7}en=\left(-\dfrac{4}{7}-\dfrac{3}{7}\right)en=\dfrac{-4-3}{7}en=\dfrac{-7}{7}en=-1en=\boxed{-en}

7 0
3 years ago
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