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3 years ago

What is volume of 4x5x8

Mathematics

1 answer:

murzikaleks [220]3 years ago

8 0

Answer:

160 is your answer

Step-by-step explanation:

4×5=20

20×8=160

You might be interested in

A quarter horse often excels at running races of 1/4 mile or less .how many feet is that

romanna [79]

Answer:

1320ft

Step-by-step explanation:

1 mile is equal to 5280 feet, divide 5280/4

this will result in a quarter mile, being 1320ft. So for the question "1/4 mile or less" the Answer is the horse excels in 1320ft mile races

3 0

3 years ago

Which of the following sets of ordered pairs does NOT describe a function?

Sophie [7]

C because one x-value can ONLY have one corresponding y-value. It cannot have more than one.

8 0

3 years ago

Show that x⁵²-21x+20 is divisible by x− 1.

SashulF [63]

Answer

given equation,

x⁵²-21 x+20

A number to be divisible by the another number means that on dividing the remainder should be zero.

if x⁵²-21 x+20 is divisible by x− 1 means that x-1 should completely divide the equation.

so,

x -1 = 0

x = 1

x⁵²-21 x+20 to be divisible it should be equal to zero when x = 1

putting x = 1

= (1)⁵²-21 (1)+20

= 1 - 21 + 20

= 21 -21

= 0

hence x = 1 is the root of the equation

so, x⁵²-21 x+20 is divisible by x− 1.

4 0

3 years ago

Lance has 3 time as many pencils as Nick, and they have 84 pencils together. How many pencils does each of them have?

Rufina [12.5K]

Answer:

21 pencils for Nick and 63 pencils for Lance

Step-by-step explanation:

Lance is said to have 3 times the pencils Nick has.
Let's keep the number of pencils Nick has as x.
If Nick has x pencils that means Lance has 3x pencils.
The total number of pencils present is 84.

Now let's make an equation out of the information above:

3x + x = 84

Now solve for x.

3x + x = 84

4x = 84

x = 84/4

x = 21

So Nick has 21 pencils

Now for Lance:

3 * (21) = 63

So Lance has 63 pencils

63 + 21 = 84 pencils

8 0

3 years ago

a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade

12345 [234]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

$P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})$

$P(at least 1 dull blade)=1-0.2931$

P(at least 1 dull blade)=0.7068

6 0

3 years ago