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3 years ago

10

A ________ exists between two variables when the values of one variable are somehow associated with the values of the other vari

able. correlation inference difference trial

1 answer:

motikmotik3 years ago

8 0

Correlation would be the correct answer

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I will give Brainliest on who answers this statement first.

ivanzaharov [21]

Answer:

hi

Step-by-step explanation:

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3 years ago

Copper has a density of 8.9 g/cm A copper necklace has a volume of 396 cm”.

Leviafan [203]

Answer:

3524.4 g

Step-by-step explanation:

Use formula: Density = Mass/Volume
Mass= Density * Volume

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3 years ago

A particular plant root grows 1.5 inches per month. How many centimeters is the plant root growing per month?

NISA [10]

Answer:3.81 centimeters

Step-by-step explanation:All you have to do is to convert inches into centimeters

So 1 inch=2.54cm

Therefore 1.5inches=(1.5/1)×2.54cm

=3.81cm

3 0

3 years ago

The answer to a,b and c

GuDViN [60]

Answer:

16/45; 4/45; 1125

Step-by-step explanation:

Since you know that 4/9 and 1/5 are used, make them common denominators. So 4/9 would turn into 20/45 and 1/5 would be 9/45. It results in 29/45, but that is the amount spent, so you would subtract 45-29/45, resulting in 16/45. For B, you know that she spent 3/4 of the savings, so you know that 1/4 is not being spent. So use 1/4 multiplied by 16/45 from part A to get 4/45. For C, you know that 4/45 is $100, so I multiplied 45x100 to get 4500 and then divided by 4 to get 4500/4.

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3 years ago

Find the quadratic function that fits the following data. which one function fits.

Oksana_A [137]

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

$y=ax^2+bx+c$

Use the data from the table:

$y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c$

We get the system of three equations:

$\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.$

Subtract these equations:

$\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.$

From the first equation

$b=-120a$

Substitute it into the second equation:

$5600a+40\cdot (-120a)=70\Rightarrow 800a=70,\\ \\ a=\dfrac{7}{80},\\ \\ b=-120\cdot \dfrac{7}{80}=-\dfrac{21}{2}=-10.5$

So,

$2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25$

The quadratic function is

$y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25$

4 0

3 years ago