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Arturiano [62]
3 years ago
10

7/13 + (-4/13) the answer has to be in simplest form.

Mathematics
2 answers:
Digiron [165]3 years ago
8 0

Answer:

short form:0.23 Long Form:0.23076923076

Step-by-step explanation:

madreJ [45]3 years ago
5 0

Answer:

3/13

Step-by-step explanation:

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Nimfa-mama [501]

Does it have any ANSWER CHOISES!

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2 years ago
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How to solve for 6x-12+2x=3+8x-15
Alecsey [184]
6x−12+2x=3+8x−15

Simplify:

6x+−12+2x=3+8x+−15

(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)

8x+−12=8x+−12


8x−12=8x−12

Subtract 8x from both sides.

8x−12−8x=8x−12−8x

−12=−12

Add 12 to both sides.

−12+12=−12+12

0=0

The real numbers are the only solution we can have.


4 0
3 years ago
Maurice earns a commission of 6,048 from the sale of a Lexus, priced at $50,400. What is Maurice's commission rate?
Nutka1998 [239]

Answer:

commission rate of Maurice is 12%

Step-by-step explanation:

Maurice earns commission = $6,048

Lexus priced at = $50,400

Maurice's commission rate =

=\frac {commision}{rate} \times 100

=\frac{6048}{50400} \times 100

=12 %

hence the commission rate of Maurice is 12%

8 0
2 years ago
How do I write 16,107,320 in expanded form?
Pani-rosa [81]
In expanded form that would be 10,000,000 + 6,000,000 + 100,000 + 7,000 + 300 + 20
3 0
2 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
2 years ago
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