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butalik [34]
3 years ago
8

the potential difference between the yellow wire and the black wire (which is attached to "ground" or zero volts) is about 4.73

volts. If the voltage across the 330 ohm resistor is 2.53 volts, then what is the value (in milliamps, where 1 milliamp = 0.001 amps) of the electric current through the resistor
Physics
1 answer:
Mariana [72]3 years ago
8 0

Answer:

The electric current through the resistor is: 7.66667 milliamps

Explanation:

Applying Ohm's law we have V = I * R or solving to I = \frac{V}{R} so now, we can replace the values given before in the equation, we need to know that the voltage across the resistor is which determine the current in the component, in this case, the resistor. After clear this topic, we get I = \frac{2.53 (volt)}{330 (ohms)} = 0.00766667 (ampers) so 1 milliamps is 0,001 amps we get 7,66667 milliamps.

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A bus decreases its speed
eduard

Answer:

-6 km/h per minute

Explanation:

7 0
3 years ago
If an object has a mass of 1417g and it is moved 47 meters in 90 seconds, how much power was used?
astraxan [27]

Mass of the object is given as

m = 1417 g = 1.417 kg

now the speed of object is given as

v = \frac{d}{t}

here we know that

d = 47 m

t = 90 s

now we will have

v = \frac{47}{90} = 0.52 m/s

now we will have kinetic energy of the object as

KE = \frac{1}{2}mv^2

KE = \frac{1}{2}(1.417)(0.52)^2

KE = 0.19 J

now the power is defined as rate of energy

so here we can find power as

P = \frac{KE}{t}

P = \frac{0.19}{90} = 2.14\times 10^{-3} W

so above is the power used for the object

3 0
4 years ago
Two gliders collide on a frictionless air track that is aligned along the x axis. Glider A has an initial velocity v0 and glider
LenaWriter [7]

Answer:

Explanation:

Applying conservation of momentum

mA v0 + 0 = mA x 12v0 + mB x 92v0

11 mA = - 92mB .

mA / mB = 92 / 11

mA : mB = 92 : 11.

3 0
3 years ago
Which of the following properties can be used to describe the wave model of light?
Naily [24]
A and c should be the answer
8 0
2 years ago
Marvin uses a long copper wire with resistivity 1.68 x 10^-8 Ω⋅m and diameter 1.00 x 10^−3​​ m to create a solenoid that has a 3
Mazyrski [523]

Answer with Explanation:

We are given that

Resistivity of copper wire=\rh0=1.68\times 10^{-8}\Omega m

Diameter=d=1.00\times 10^{-3} m

Radius of copper wire=r=\frac{d}{2}=\frac{1}{2}\times 10^{-3} m

Radius of solenoid=r'=3 cm=3\times 10^{-2} m

1 m=100 cm

a.Length of wire=l=11.3 m

Area of wire=A=\pi r^2

Where \pi=3.14

A=3.14\times (\frac{1}{2}\times 10^{-3})^2

Resistance, R=\rho \frac{l}{A}

Using the formula

R=1.68\times 10^{-8}\times\frac{11.3}{3.14\times (\frac{1}{2}\times 10^{-3})^2}

R=0.24\Omega

B.Length of solenoid=2\pi r'=2\times 3.14\times 3\times 10^{-2}=0.188 m

Number of turns=n_0=\frac{l}{2\pi r'}=\frac{11.3}{0.188}

n_0=60

C.Potential difference,V=3 V

Current,I=\frac{V}{R}

I=\frac{3}{0.24}=12.5 A

D.Total length =0.1 m

Number of turns per unit length,n=\frac{60}{0.1}=600

Magnetic field along central axis inside of the solenoid,B=\mu_0 nI

B=4\pi\times 10^{-7}\times 12.5\times 600=9.42\times 10^{-3} T

4 0
3 years ago
Read 2 more answers
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