To solve this problem we will apply the concepts related to Ohm's law and Electric Power. By Ohm's law we know that resistance is equivalent to,

Here,
V = Voltage
I = Current
While the power is equivalent to the product between the current and the voltage, thus solving for the current we have,


Applying Ohm's law


Therefore the equivalent resistance of the light string is 
Answer:
Option 3
Explanation:
O Option C is NEGATIVELY CHARGED, meaning it has GAINED ELECTRONS resulting in a GREATER number of ELECTRONS than PROTONS.
Answer:
the total mass is 35 kg
k.E = 1/2 mv2
43.76 =1/2 v2
v2=2×43.76
Explanation:
v=radicls 87.52 which is equal to 9.5 m/s
Answer:
The flow of electric charge
Explanation:
Electricity:It is defined flow of electric charge.
It is defined as the flow of charge per unit time.
Electric charge can be negative or positive .
Mathematical representation :
If charge Q flowing through the conductor and time taken in flow of charge is t seconds.
Then, current
S.I unit of current is Ampere.It is scalar quantity.
Answer:The flow of electric charge.