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3 years ago

What are the 2 types of shadow cast by the moon during a solar eclipse?

Physics

2 answers:

Colt1911 [192]3 years ago

6 0

The person above me is correct.

Paha777 [63]3 years ago

3 0

Answer:

umbra, penumbra

Explanation:

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How do electromagnetic forces work?

zlopas [31]

It attracts two charged particles which are separated by a definitive distance.......

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4 years ago

Nearly all light that strikes a(n) ______ object will be absorbed by the object.

belka [17]

Nearly all light that strikes a transparent object will be absorbed by the object.

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4 years ago

Read 2 more answers

A person is standing on a spring bathroom scale on the floor of an elevator which is moving up and slowing down at the rate of 3

aleksklad [387]

Answer:

$F_N=1194.24\ N$

Explanation:

Given that,

The elevator is moving up and slowing down at the rate of, $a=3\ m/s^2$

The acceleration due to gravity, $g=9.8\ m/s^2$

Mass of the person, m = 93.3 kg

To find,

The reading of the scale.

Solution,

As the elevator is moving down with some acceleration. The net force acting on it is given by :

$F_N=ma+mg$

$F_N=m(a+g)$

$F_N=93.3(3+9.8)$

$F_N=1194.24\ N$

So, the scale will read 1194.24 N.

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4 years ago

Boojho made light from a laser torch to fall on a prism. Will he be able to observe a band

fgiga [73]

Answer:

It depends on whether it is a white light that hits the prison.

Explanation:

If the light from the laser is not white then he wont be able to see all seven colours because it is only a white light that absorbs other colours and when it hits the prism it will refract and therefore he will see all seven colours

7 0

3 years ago

A 520kg rocket sled at rest is propelled along the ice by an engine developing a constant thrust of 12 000 N over a distance of

Maurinko [17]

<u>Answer:</u>

a) 480 000 J

b) 43 m/s

<u>Explanation:</u>

To calculate the work done by the engine, we can use the following formula:

$\boxed{\mathrm{Work \space\ done = Force \times Distance}}$ .

⇒ $12000 \times 40$

⇒ $480000 \space\ \mathrm J$

We know that the work done by the propeller was converted into motion of the sled, which means the propeller provided the sled with kinetic energy.

∴ work done by propeller = kinetic energy gained by sled

⇒ $480000 = \frac{1}{2} mv^2$

⇒ $480000 = \frac{1}{2} \times 520 \times v^2$

⇒ $480000 = 260v^2$

⇒ $v^2 = \frac{480000}{260}$

⇒ $v =\bf 43 \space\ m/s$

This means that its velocity after 40 m was 43 m/s.

4 0

2 years ago