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rodikova [14]
3 years ago
6

What is 2/8 plus 3/8 plus 4/8?

Mathematics
2 answers:
Iteru [2.4K]3 years ago
5 0
Ok, so we are going to do 2/8 + 3/8 + 4/8. The first thing we are going to do is 2/8 + 3/8. 2/8 + 3/8 = 5/8. Now, we are going to do 5/8 + 4/8. 5/8 + 4/8 = 9/8. We are going to divide because 9 is bigger than 8. 9÷8=1 remainder of 1. So, Therefore, your answer is \boxed{1 \frac{1}{8}}
Alja [10]3 years ago
4 0
9/8 becuase the bottom number is the same so you just add the top numbers 2+3+4=9 and you just keep the 8th as they are
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Answer:

3x²+12x

Step-by-step explanation:

Expand the brackets

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4 years ago
What is the sign of −4ab when a&gt;0 and b&lt;0?
AVprozaik [17]

Answer:

A

Step-by-step explanation:

We have the expression:

-4ab

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Notice that the expression is already negative since we have -4.

a>0 means that a is positive. Therefore, we can ignore it since it won’t do anything.

b<0 means that b is negative. Therefore, we will have two negatives being multiplied together. Hence, this will make a positive.

Therefore, the sign of our expression will be positive.

We can see this with an example. Let a=1 (1>0) and let b=-1 (-1<0). Then:

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7 0
3 years ago
Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

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4 years ago
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aleksklad [387]

Answer:

He switched the divisor and the dividend when creating an equation to model the problem in step 1.

Step-by-step explanation:

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lina2011 [118]
-5/2

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