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denis-greek [22]
3 years ago
6

What is the sign of −4ab when a>0 and b<0?

Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

A

Step-by-step explanation:

We have the expression:

-4ab

And we want to find its sign given that a>0 and b<0.

Notice that the expression is already negative since we have -4.

a>0 means that a is positive. Therefore, we can ignore it since it won’t do anything.

b<0 means that b is negative. Therefore, we will have two negatives being multiplied together. Hence, this will make a positive.

Therefore, the sign of our expression will be positive.

We can see this with an example. Let a=1 (1>0) and let b=-1 (-1<0). Then:

-4(1)(-1)=4

So, the sign is positive.

Hence, the answer is A.

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6 0
3 years ago
A piece if wire 40cm is bent to form a right angled triangle whose hypotenuse is 17cm long find the other two sides of triangle
hjlf

Answer: 150mm

Step-by-step explanation:

Take the two adjecent sides of the triangle to be x and y and X is the angle opposite the side, x.

From the trigonometric identities for a right-angled triangle, it is known that

x=170sin X and;

y=170cos X

Thus the perimeter of the triangle is given by

170sin X + 170cos X + 170 = 400

170(sin X + cos X) = 400 - 170

170(sin X + cos X) = 230

sin X + cos X = 230/170 = 1.3529

Squaring both sides hence,

sin^2(X) + 2sin X.cos X + cos^2(X) = 1.8304

Recall that sin^2(X) + cos^2(X) = 1 and 2sin X.cos X = sin 2X.

Thus, the former expression gives;

1 + sin 2X = 1.8304

sin 2X = 0.8304

2X = arcsin (0.8304)

2X = 56.14° or (180 - 56.14)° = 56.14° or 123.86° for X existing within a triangle.

X = 56.14/2 or 123.86/2

X = 28.07° or 61.93°

Thus the two adjacent sides are ;

x = 170 sin (28.07) = 80mm

y = 170 cos (28.07) = 150mm

Using the value of 61.93° as X would give the same values but interchanged for x and y.

I hope you find this useful.

5 0
3 years ago
Does the equation 2x + 3 = 11 go through the point (1,4)?
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3 years ago
SOLVE THIS EXTREMELY IMPORTANT EQUATION
finlep [7]

Answer:

<em>Option B; EF = ( About ) 4.47 units, Perimeter of Δ EFG = ( About ) 12.94 units</em>

Step-by-step explanation:

If we were to consider the height of this triangle EFG, it would be 4 units of length, supposedly splitting base GF into two ≅ parts, each 2 units of length. First let us name the point drawn to base GF ⇒ point H, so that the height of Δ EFG ⇒ EH. Now as EH splits GF into two ≅ parts, by Converse to Coincidence Theorem, Δ EFG ⇒ Isosceles Δ;

EH and FH are legs of a right triangle EFH, so that Pythagorean Theorem can be applied to solve for the length of EF and EG, knowing that as Δ EFG ⇒ Isosceles Δ, EF ≅ EG;

( EH )^2 + ( FH )^2 = ( EF )^2,

( 4 )^2 + ( 2 )^2 = ( EF )^2 ⇒ take square of 4 & 2,

16 + 4 = ( EF )^2 ⇒ combine like terms,

( EF )^2 = 20 ⇒ take square root on either side to solve for EF,

EF = √ 20 =<em> ( About ) 4.47 units</em> = EG,

Perimeter of Δ EFG = EF + GF + EG = 4.47 + 4 + 4.47 = <em>( About ) 12.94 units,</em>

<em>Solution; Option B</em>

6 0
3 years ago
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