Question 1:
For this case we must find the value of the following expression:

So we have to:

Substituting we have:

Thus, the value of the expression is 37.
Answer:

Option C
Question 2:
For this case we have the following expression:

We must simplify it!
We have to:

Rewriting the expression we have

2 times 9 is 18.
Finally we have to:

Answer:

Option B
Question 3:
For this case we have that by definition, the perimeter of a square is given by:

Where:
l: It's the side of the square
In this case they tell us that:

Thus:

Now we must do a conversion. By definition we have to:
1 foot equals 12 inches. So:

Answer:
The perimeter of the garden is 
Question 4:
For this case we have to:
Let "p" be the variable that represents the number of pages Nora read yesterday.
If today I read 6 more than yesterday, then we can write the following expression:

So, the number of pages that Nora read today is 
ANswer:
The number of pages that Nora read today is
Question 5:
For this case we have that by definition, the area of a triangle is given by:

Where:
b: It is the base of the triangle
h: It is the height
We have as data that:

Substituting we have:
The area of the triangle is
Answer:
Option B