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kvasek [131]
3 years ago
7

Solve for x: 5x + one third(3x + 6) > 14

Mathematics
2 answers:
alekssr [168]3 years ago
5 0

Answer:

The correct option is B) x > 2.

Step-by-step explanation:

Consider the provided inequality.

5x+\frac{1}{3}(3x+6)>14

Distributive property:

a(b+c)=ab+ac

By the distributive property.

5x+\frac{1}{3}\times 3x+\frac{1}{3}\times 6>14\\5x+x+2>14

Add the like terms

6x+2>14

Subtract 2 from both sides.

6x+2-2>14-2\\6x>12

Divide both sides by 6.

\frac{6x}{6}>\frac{12}{6}\\x>2

Hence, the correct option is B) x > 2.

MA_775_DIABLO [31]3 years ago
4 0

Answer:

It should be x > 2

Step-by-step explanation:

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(08.06)The following data show the weight, in ounces, of 10 different bags of candy: 10 3 7 3 4 21 6 10 1 2 4 After removing the
hoa [83]

Answer:

B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.

To find the mean absolute deviation, we first find the mean.  Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):

(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5

Now we find the difference between each data point and the mean, take its absolute value, and find their sum:

|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =

5+2+2+2+1+1+5+4+3+1 = 26

We now divide this by the number of data points:

26/10 = 2.6

This is a measure of how much each bag of candy varies from the mean.

4 0
3 years ago
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Answer: c.+dhf+2-4= 6)

Step-by-step explanation: Hope this helps!

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3 years ago
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3 years ago
Find the angle between u = (8.- 3) and v = (-3,- 8) Round to the nearest tenth of a degree.
Nimfa-mama [501]

Answer:

<h2>90°</h2>

Step-by-step explanation:

First you must calculate the module or the magnitude of both vectors

The module of u is:

|u|=\sqrt{(8)^2 + (-3)^2} \\\\|u|=\sqrt{64 + 9}\\\\|u|=8.544

The module of v is:

|v|=\sqrt{(-3)^2 + (-8)^2} \\\\|u|=\sqrt{9 + 64}\\\\|u|=8.544

Now we calculate the scalar product between both vectors

u*v = 8*(-3) + (-3)*(-8)\\\\u*v = -24+ 24=0

Finally we know that the scalar product of two vectors is equal to:

u*v = |u||v|*cos(\theta)

Where \theta is the angle between the vectors u and v. Now we solve the equation for \theta

0 = 8.544*8.544*cos(\theta)\\\\0 = cos(\theta)\\\\\theta= arcos(0)\\\\\theta=90\°

the answer is 90°

Whenever the scalar product of two vectors is equals to zero it means that the angle between them is 90 °

5 0
3 years ago
Read 2 more answers
How many multiples of 4 are there in {n; 37&lt; n &lt;1001}?
s2008m [1.1K]
Let's begin by listing the first few multiples of 4:  4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44.  So, between 1 and 37 there are 9 such multiples:  {4, 8, 12, 16, 20, 24, 28, 32, 36}.  Note that 4 divided into 36 is 9.

Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:

<span>How many multiples of 4 are there in {n; 37< n <101}?  We could list and then count them:  {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval.  Try subtracting 40 from 100; we get 60.  Dividing 60 by 4, we get 15, which is 1 less than 16.  So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:

1000
   -40
-------
 960

Dividing this by 4, we get 240.  Adding 1, we get 241.

Finally, subtract 9 from 241:  We get 232.

There are 232 multiples of 4 between 37 and 1001.

Can you think of a more straightforward method of determining this number? </span>

5 0
3 years ago
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