John writes the proof below to show that the sum of the angles in a triangle is equal to 180º.
1 answer:
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Answer:
Step-by-step explanation:
Given
Required
Determine the difference
Represent this with d.
d is calculated using
The equation becomes
Answer:
Step-by-step explanation:
(a)
let, f(x) = 2x+1 & g(x) = 2x+2
So, f(x).g(x) = (2x+1).(2x+2) = 4x² + 6x + 2 = 2x+2 in
So, product of two 1 degree polynomials is a 1-degree polynomial in
(b)
let, f(x) = 2x³ - 3x² + 5x + 7 & g(x) = -2x³ + 3x² + x + 3 be two polynomials in R[x]
So, f(x) + g(x) = 6x + 10, which is a polynomial of degree 1 in R[x]
(c)
this is not possible, since, if f & g are 2 polynomials in any polynomial ring S, then, we always have,
deg(f.g) <= deg(f) + deg(g)
So, deg(f.g) = 5 (as desired) but, deg(f) + deg(g) = 2+2 = 4 but, 4 < 5
So, this is not possible.
So, no such example exists.