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Naily [24]
3 years ago
12

Find the radius of the circle circumscribed around an equilateral triangle, if the radius of the circle inscribed into this tria

ngle is 10 cm.

Mathematics
2 answers:
ss7ja [257]3 years ago
6 0

Answer:

20 cm

Step-by-step explanation:

Let a cm be the length of the side of equilateral triangle.

Use formula for the radius of inscribed circle into the equailteral triangle:

r_{inscribed}=\dfrac{a\sqrt{3}}{6}

Hence,

\dfrac{a\sqrt{3}}{6}=10\Rightarrow a=\dfrac{60}{\sqrt{3}}

Now, use formula for the circumscribed circle's radius:

R_{circumscribed}=\dfrac{a\sqrt{3}}{3}

Therefore,

R_{circumscribed}=\dfrac{\frac{60}{\sqrt{3}}\cdot \sqrt{3}}{3}=20\ cm

Aliun [14]3 years ago
4 0

Answer:

<h2>20 cm</h2>

Step-by-step explanation:

Look at the picture.

The formula of a radius of a circle circumscribed around an equaliteral triangle:

R=\dfrac{2}{3}\cdot\dfrac{a\sqrt3}{2}

The formula od a radius of a circle inscribed into an equaliteral triangle:

r=\dfrac{1}{3}\cdot\dfrac{a\sqrt3}{2}

As you can see in the formulas above, the radius of the circumscribed circle is twice the radius of the inscribed circle.

Therefore

R=2r

Given:

r=10\ cm

therefore

R=2(10\ cm)=20\ cm

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The authors of a paper describe an experiment to evaluate the effect of using a cell phone on reaction time. Subjects were asked
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Answer:

a) The 99% confidence interval would be given by (24.409;24.979)  

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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Part a

The confidence interval for the mean is given by the following formula:  

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In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=47-1=46  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

525-2.01\frac{75}{\sqrt{47}}=503.01  

525+2.01\frac{75}{\sqrt{47}}=546.99  

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:  

ME=t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{t_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, t_{\alpha/2}=2.01 from part a, replacing into formula (2) we got:  

n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464  

So the answer for this case would be n=464 rounded up to the nearest integer  

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