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I am Lyosha [343]
3 years ago
9

In the equation 3a+2(4a-1)=9 what is value of a ?

Mathematics
2 answers:
MrMuchimi3 years ago
7 0
Here is the answer
I did it with steps
3a+2(4a-1)=9
3a+8a-2=9
11a=11
a=1
Temka [501]3 years ago
5 0
3a+2(4a-1) = 9
3a+8a-2 = 9
11a -2= 9
plus 2 to get rid of the minus 2 and plus 2 to 9 aswell
11a=11
a=1
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Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is 2

Part 2) The vertex is the point (1,8)

Part 3) The equation of the axis of symmetry is x=1

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is y=2x^{2}-4x+10

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

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x=h

In this problem we have

y=2(x-1)^{2}+8 -----> this is the equation in vertex form of a vertical parabola

The value of a=2

so

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point (1,8)

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(h,k)=(1,8)

The equation of the axis of symmetry is x=1

The equation of a vertical parabola in standard form is equal to

y=ax^{2}+bx+c

Convert vertex form in standard form

y=2(x-1)^{2}+8

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y=2x^{2}-4x+2+8

y=2x^{2}-4x+10

see the attached figure to better understand the problem

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Hey there,

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Answer:

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Step-by-step explanation:

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