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4 years ago

In the equation 3a+2(4a-1)=9 what is value of a ?

Mathematics

2 answers:

MrMuchimi4 years ago

7 0

Here is the answer
I did it with steps
3a+2(4a-1)=9
3a+8a-2=9
11a=11
a=1

Temka [501]4 years ago

5 0

3a+2(4a-1) = 9
3a+8a-2 = 9
11a -2= 9
plus 2 to get rid of the minus 2 and plus 2 to 9 aswell
11a=11
a=1

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erastovalidia [21]

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<h3>The option B) is correct</h3><h3>Therefore the coordinate of B $(x_2,y_2)$ is (6,-3)</h3>

Step-by-step explanation:

Given that the midpoint of segment AB is (4, 2). The coordinates of point A is (2, 7).

<h3>To Find the coordinates of point B:</h3>

Let the coordinate of A be $(x_1,y_1)$ is (2,7) respectively
Let the coordinate of B be $(x_2,y_2)$
And Let M(x,y) be the mid point of line segment AB is (4,2) respectively
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Now substitute the coordinates int he above formula we get
$(4,2)=(\frac{2+x_2}{2},\frac{7+y_2}{2})$
Now equating we get

$4=\frac{2+x_2}{2}$ $2=\frac{7+y_2}{2}$

Multiply by 2 we get Multiply by 2 we get

$4(2)=2+x_2$ $2(2)=7+y_2$

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Subtracting 2 on both

the sides Subtracting 7 on both the sides

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Rewritting the above equation Rewritting the equation

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