The answer is for this question is true
Answer:
A function that has an axis of symmetry at x = 3 is:
f (x) = x ^ 2 - 6x - 1
Step-by-step explanation:
A parabola has an axis of symmetry at x = 3 if the x-value of the vertex is 3.
f(x) = x^2 + 3x + 1 = x^2 + 3x + 9/4 - 5/4 = (x + 3/2)^2 - 5/4 => vertex = (-3/2, -5/4)
f(x) = x^2 - 3x - 3 = x^2 - 3x + 9/4 - 21/4 = (x - 3/2)^2 - 21/4 => vertex = (3/2, -21/4)
f(x) = x^2 + 6x + 3 = x^2 + 6x + 9 - 6 = (x + 3)^2 - 6 => vertex = (-3, -6)
f(x) = x^2 - 6x - 1 = x^2 - 6x + 9 - 10 = (x - 3)^2 - 10 => vertex = (3, -10)
Therefore, f(x) = x^2 - 6x - 1 has an axis of symmetry at x = 3.
Hope This HELPS!!!
Answer:
Step-by-step explanation:
Step 1: First apply radical rule in the given expression.
![\sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Here, ![\sqrt[3]{7}=7^{\frac{1}{3}}, \sqrt[5]{7}=7^{\frac{1}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%2C%20%5Csqrt%5B5%5D%7B7%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D)
The expression becomes ![\frac{\sqrt[3]{7}}{\sqrt[5]{7}}=\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B7%7D%7D%7B%5Csqrt%5B5%5D%7B7%7D%7D%3D%5Cfrac%7B7%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%7B7%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%7D)
Step 2: Now, apply exponent rule in the above expression
So, the expression becomes, 
.
Step 3: Take cross multiply the denominator and numerator of the fraction in the power of 7.
The answer is .
Hence the simplified form of ![\frac{\sqrt[3]{7}}{\sqrt[5]{7}}=7^{\frac{2}{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B7%7D%7D%7B%5Csqrt%5B5%5D%7B7%7D%7D%3D7%5E%7B%5Cfrac%7B2%7D%7B5%7D%7D)
.
Answer:
yes es correcto ya que 70 es igual a 4 metros
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