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3 years ago

5

Charlene bought a used.It cost $43.00.A new skateboard costs 3 times as much as the used one Charlene bought.How much does a new

skateboard cost?

1 answer:

vovangra [49]3 years ago

6 0

Multiply it by 3.
43.00*3=129=priceNewSkateboard

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Suppose x represents an objects weight on Earth. Write two expressions: one that you can use to find the objects weight on Mars

tatyana61 [14]

The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.

4 0

3 years ago

The denominator of a fraction is 9 more than the numerator. if both the numerator and the denominator are decreased by 1 the res

yarga [219]

X/x+9 (original fraction)

x+1/ x+10 = 4/13

x+1=4 so x=3 and x+10=13 so again x=3

now that you have the value of x, substitute it into the original fraction to get:

3/12

5 0

3 years ago

HELP!!!! PLEASE I NEED HELP!!!!

NNADVOKAT [17]

for the first one it is the second option because of one property of logarithms:

log(a)-log(b)=log $\frac{a}{b}$

for the second one using the same property we can say that we third option is correct and not the second one but we use one more property of the logarithm

loga(b)^x=xloga(b) the power of the logarithm becomes a fator and $\sqrt[3]{x}$ is equal to $x^{\frac{1}{3}}$

8 0

3 years ago

Help please I'm stuck show and explain your work

Deffense [45]

The expressions D, E, and F represent a correct solution to the equation.

Step-by-step explanation:

Step 1:

First, we need to solve the given equation and find the value of x which satisfies the equation.

$6(x+4)=20, (x+4) = \frac{20}{6} = 3.333,$

$x = 3.333 - 4 = -0.666.$

So the value of x for the given equation is -0.666.

Step 2:

Now we evaluate the values of the six given options to see which ones have an x value of -0.666.

A. $\frac{20-4}{6}= \frac{16}{6} = 2.666,$

B. $\frac{1}{6} (20-4)= \frac{1}{6} (16)=\frac{16}{6} = 2.666,$

C. 20 -6 -4 = 20 - 10 = 10.

D. $\frac{20}{6} -4= 3.333 - 4 = -0.666,$

E. $\frac{1}{6} (20-24) = \frac{1}{6} (-4)= -0.666,$

F. $(20-24)\frac{1}{6} = (-4)\frac{1}{6} = -0.666.$

So the options D, E, and F represent a correct solution to the given equation.

7 0

4 years ago

The senior classes at High School A and High School B planned separate trips to New York City. The senior class at High School A

Nezavi [6.7K]

Class A: 6v + 8b = 202

Class B: 12v + 16b = 284

Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:

12v + 16b = 404
12v + 10b = 284

Then subtract the bottom equation from the top:

6b = 120
b = 20

Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:

6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7

So then you know that each van can hold 7 students.

Check:
12 (7) + 10 (20) = 284

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3 0

4 years ago