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muminat
2 years ago
15

The market bought grapes for $0.87 a pound and sold them for $1.09 a pound. What is the percent for increace rounded to the near

est tenth?
Mathematics
1 answer:
Len [333]2 years ago
5 0
So to find percent increase, you want to minus the difference in cost..

1.09- 0.87= .22...

now divide the difference by the original....

.22 ÷ .87 = .25287.....etc

now multiply that by 100...

.25287 × 100 = 25.287

now it says round to the nearest tenth so...

25.29% increase.

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Please help :c
miss Akunina [59]

Answer: $17.55

Step-by-step explanation:

36 x 0.65 = $23.40 total for all cookies

($23.40/1) x (3/4) = (70.2/4)

70.2 divided by 4 = $17.55

or

$23.40 x .75 = $17.55

4 0
2 years ago
Simplify the following complex fraction.(3/7---1/3)2/3-----1/7
Yakvenalex [24]
Please retype this fraction.  If by "---" you mean "subtraction," type 3/7-1/3.

Let's assume that the problem is as follows:  (3/7-1/3)(2/3)-1/7;
first, find the LCD of 3/7 and 1/3 and then combine 3/7 and -1/3).
second, multiply your result by (2/3).
third, subtract 1/7 from your result.

If, however, your "---" and "-----" mean "division, then the above is all wrong.

If that's the case, then please retype your whole question.

You could express "the quotient of 2/3 and 1/6" as follows:
   
            2
          ----
            3

------------------------
            1
          -----
             6

Is that what you meant?

Sorry to be picky, but it's very important that you express math properly.





4 0
3 years ago
Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
Alona [7]

Answer:

We have the equation

c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

4 0
3 years ago
A certain experimental mathematics program was tried out in 2 classes in each of 32 elementary schools and involved 37 teachers.
zheka24 [161]

Answer:

A) 0 and 13

Step-by-step explanation:

64 - 37 = 27

27/2 = 13.5

13 teachers can teach 3 classes at max

6 0
3 years ago
And are perpendiculars dropped from to , and is perpendicular to and . If CR = DS, which statement must be true?
Ghella [55]
The answer is m rcd= m acd divided by 3
5 0
3 years ago
Read 2 more answers
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