The answer is 5 and associative property
Answer:
Here you go.Hope this help!!
For each of the following relationships, graph the proportional relationship between the two quantities, write the equation representing the relationship, and describe how the unit rate, or slope is represented on the graph.
Answer:
Exact dimensions:



Approximate dimensions:



Step-by-step explanation:
Let's assume width of rectangle is w ft
The length of a rectangular flower bed is 2ft longer than the width
so,
length =w+2

now, we can find area

now, we can plug it


we are given area =6
so, we can set it equal
and then we can solve for w


we can use quadratic formula


now, we can compare and find a,b and c
a=1 , b=2 , c=-6


we know that dimension can never be negative
so, we will only consider positive value
Exact dimensions:



Approximate dimensions:



For part A add up all your students then add up all your students that like bike riding and skating (80+90) divide that by the total number of students who took the survey
For Part be put 20+40 over the toatl number of student then simplify