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Andrews [41]
2 years ago
12

Find the angles please please

Mathematics
1 answer:
IceJOKER [234]2 years ago
6 0
Angle BAC
cosφ⁻¹ = (10² + 17² - 11²)/(2*10*17) = 37.9 ≈ 38°
Angle ACB
cosφ⁻¹ = (10² + 11² - 17²)/(2*10*11) = 108.0°
Angle ABC
cosφ⁻¹ = (11² + 17² - 10²)/(2*11*17) = 34.0°
See you !
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-4x - 6x = -20 =?<br><br> -3(2x - 3) = 33 = ?<br><br> 4x + 3x + 2x = 180 = ?
postnew [5]

Answer:

-4x-6x=-20=

x=2

-3(2x-3)=33=

x=-4

4x+3x+2x=180

x=20

Step-by-step explanation:

-4x-6x=-20                                

-4+(-6)=-10x

-10x=20 (divide both by 10)

x=-2 (divide by -1 to get positive)

x=2

-3(2x-3)=33

-6x+9=33

     -9 .  -9

-6x=24 (divide both by -6)

x=-4 (divide by -1 to make positive)

4x+3x+2x=180

(combine like terms)

9x=180 (divide both sides by 9)

x=20

5 0
2 years ago
Which expression is equivalent to 4/9 x 7​
Romashka [77]

Answer:

I think it is 3.1

Step-by-step explanation:

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8 0
2 years ago
A function has the function rule y = x - 7. If the input is 4, what is the output?
Troyanec [42]

Answer:

-3

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
NEED HELP ASAP PLEASE WITH EXPLANATION PLEASE
KonstantinChe [14]

Answer:

(1) 20%

Step-by-step explanation:

→ Find the difference in price

200 - 160 = 40

→ Divide difference by original price

40 ÷ 200 = 0.2

→ Multiply the answer by 100

0.2 × 100 = 20%

7 0
3 years ago
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
2 years ago
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