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spayn [35]
3 years ago
12

What new scientific evidence led to changes in Dalton's atomic theory?

Chemistry
1 answer:
Masja [62]3 years ago
6 0

Drawbacks of Dalton's Atomic Theory. The indivisibility of an atom was proved wrong: an atom can be further subdivided into protons, neutrons and electrons. However an atom is the smallest particle that takes part in chemical reactions. According to Dalton, the atoms of same element are similar in all respects.

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what is the mole fraction of ethanol c2h5oh in an aqueous solution that is 46 perccent ethanol by mass?
kari74 [83]

The mole fraction of ethanol c2h5oh in an aqueous solution that is 46 percent ethanol by mass is 0.25

Mole fraction is the mole of one of the component of the solution divided by the total moles of the solution

Calculating the mole fraction of ethanol,we get

Percentage by weight of ethyl alcohol is 46% which implies in 100 g of this solution is 46 g while the mass of the water will be 54% of 100 g = 54g.

Finding the moles of water and the ethyl alcohol {molar mass of water(H₂O) = 18 and molar mass of ethyl alcohol(C₂H₆O = 46}

Moles = mass/molar mass

moles of ethanol = 46/46 = 1

moles of water = 54/18 = 3

ntotal=1+3=4

Mole fraction of ethanol is:

  Mole of ethanol            =   1/4

   Total mole of solution

Hence, the mole fraction is 1/4 or 0.25

To learn more about mole fraction visit:

brainly.com/question/8076655

#SPJ4

7 0
2 years ago
Which of the following is true about homogeous mixtures
sergey [27]
Was there supposed to be a picture?
4 0
3 years ago
The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
3 years ago
(a) Write the reaction for the overall oxidation of propane (C3H8) with oxygen to produce CO2 and water.
Pavlova-9 [17]

Answer:

Oxidation is the loss of electrons, that is, addition of electronegetive elements, example is addition of oxygen. Also, removal of electropositive elements, example is removal of hydrogen.

Explanation: a) In the presence of excess oxygen, propane burns in air, which gives the following chemical equation:

C3H8 + 5O2⇒ 3CO2 + 4H2O +Heat

b) When insufficient oxygen or too much oxygen is present for complete combustion, the following equation is given:

2C3H8 + 9O2 ⇒ 4CO2 + 2CO + 8H2O + Heat

c) At the anode( negative terminal): O∧2- ⇒ O + e

Oxygen accepts electron.

d) At cathode ( positive terminal): H∧+ + e∧- ⇒ H

Hydrogen donates electron

d) Nernst equation for reversal potential is given as follows:

E= RT/zF  In{ion outside cell}/{ion inside cell}= 2.303 RT/zF In{ion outside cell}/{ion inside cell}

4 0
4 years ago
Please help me (40 points)
Maksim231197 [3]

Answer:

P=15

N=16

Explanation:

4 0
3 years ago
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