All categories

2 years ago

PLZ HELP! I will give brainliest for best answer!!!!

Chemistry

1 answer:

AnnZ [28]2 years ago

4 0

Nitrogen is 1.25 g/L

Sulfur Dioxide is 2.86 g/L

Methane is 0.174 g/L

Hope I helped :)

You might be interested in

What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is 4.65 got copper is produced when 1.87 grams of

marta [7]

Answer:

Percent yield = 69.4%

Explanation:

Given data:

Percent yield = ?

Actual yield of copper = 4.65 g

Mass of aluminium = 1.87 g

Mass of copper sulfate = excess

Solution:

Chemical equation:

2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu

Number of moles of Aluminium:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of Al with copper.

Al : Cu

2 : 3

0.07 : 3/2×0.07 =0.105 mol

Mass of Copper:(Theoretical yield)

Mass = Number of moles × molar mass

Mass = 0.105 mol × 63.5 g/mol

Mass = 6.7 g

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 4.65 g/ 6.7 g × 100

Percent yield = 69.4%

4 0

3 years ago

If the molar mass of the compound in problem 3 is 73.8 grams/mole? what is the molecular formula ?

umka21 [38]

The molecular formula would be Li2CO3

7 0

2 years ago

A fixed mass of a gas occupies 1000cm

Serhud [2]

Answer:

the pressure of gas is 100.0 the volume is 500.0

Explanation:

4 0

2 years ago

By definition, all acids are harmful for human beings. true or false

bixtya [17]

Answer:

true

Explanation:

7 0

2 years ago

Read 2 more answers

Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I

Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, $1.077\times 10^9$

Explanation :

First we have to calculate the moles of iron.

$\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles$

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains $6.022\times 10^{23}$ number of iron atoms

So, 0.0519 mole of iron contains $0.0519\times 6.022\times 10^{23}=3.125\times 10^{22}$ number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = $\frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}$

Number of iron atoms are present in each red blood cell = $\frac{3.125\times 10^{22}}{2.90\times 10^{13}}$

Number of iron atoms are present in each red blood cell = $1.077\times 10^9$

Therefore, the number of iron atoms present in each red blood cell are, $1.077\times 10^9$

6 0

2 years ago