The average rate of change over some interval [a, b] is equal to the slope of the secant line from (a, h(a)) to (b, h(b)).
h(t) is a quadratic function, so its graph is a parabola, and in particular it's one that has a minimum of -4 when t = 2.
The secant line over an interval [a, b] will have a negative slope if the distance from a to 2 is larger than the distance from b to 2.
(A) If a = 4 and b = 5, then |a - 2| = 2 and |b - 2| = 3, so the slope and hence average rate of change is positive.
(B) If a = -1 and b = 5, then |a - 2| = 3 and |b - 2| = 3, so this ARoC is zero.
(C) If a = 0 and b = 4, then |a - 2| = 2 and |b - 2| = 2, so this ARoC is also zero.
(D) If a = -1 and b = 4, then |a - 2| = 3 and |b - 2| = 2, so this ARoC is negative.
For
ax+by=c
slope=-a/b
we have
-6x+1y=-4
slope=-6/-1=6
slope is 6
yint is where x=0
-6(0)+y=-4
0+y=-4
y=-4
yint is at y=-4 or (0,-4)
Answer: B. Y= 0x + 0
Step-by-step explanation: It's a straight line to the alienbecause it's straight down the x-axis
Hope this helped!
Expressed a proper fraction in its simplest form, 0.79 is equal to 79/100, or this seventy-nine hundredths