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malfutka [58]
3 years ago
15

Please help me with this math problem (having trouble)

Mathematics
2 answers:
babymother [125]3 years ago
5 0

Answer:

A≈2026.8

Explanation:

By using the formula,

A=2πd/ 2h+2π(d /2)^2

we can find the surface area of the cylinder.

(PS. dont mess up your order of operations!)

Hope it helps!

dezoksy [38]3 years ago
4 0

Answer: 2025.80ft^2

Step-by-step explanation:

Formula: A=2\pi rh+2\pi r^2

Diameter: 25.4ft

Height: 12.7ft

Radius: \frac{d}{2}=\frac{25.4ft}{2}=12.7ft

A=2(3.14)(12.7ft)(12.7ft)+2(3.14)(12.7ft)^2\\A=1012.90ft^2+1012.90ft^2\\A=2025.80ft^2

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kvasek [131]
Ok so

8000=cost
profit-8000
then
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but profit of 35 rand
35-15=20
profit of 20rand per mug

profit=R20m-8000
where m=number of mugs sold
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f(m)=R20m-8000
6 0
4 years ago
If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what
Lisa [10]
\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}

\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}
5 0
3 years ago
Jayne is studying urban planning and finds that her town is decreasing in population by 3% each year. The population of her town
katen-ka-za [31]
This statement is in fact true
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3 years ago
Simply the following expression: 2p x 3r x 5p
Neporo4naja [7]

Answer:

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2p ×3r×5p

group like terms

2p×5p×3r

10p squared × 3r

6 0
3 years ago
The function h(t) = 210 – 15t models the altitude of a hot air balloon over time t, in minutes.
Mila [183]
If we substitute 10 for t we get the height of the balloon after being in the air 10 minutes

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7 0
3 years ago
Read 2 more answers
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