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Harman [31]
2 years ago
8

Help me quick please

Mathematics
2 answers:
Ira Lisetskai [31]2 years ago
8 0

Answer:

<u>9⁹</u>

Step-by-step explanation:

both bases are 9 thus the base stays the same

9=?

since we're multiplying we are gonna add the powers:

⁷+²=⁹

thus...

9⁷×9²

<u>=9⁹</u>

Hope this helped you- have a good day bro cya)

Semmy [17]2 years ago
7 0

Answer:

9^9

Step-by-step explanation:

9^7×9^2

9^7+^2

^7+^2=9

9^9

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use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 )​, (15 comma
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Answer:

volume V of the solid

\boxed{V=\displaystyle\frac{125\pi}{12}}

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.  

Each slice is a quarter of cylinder 5/n thick and has a radius of  

-k(5/n) + 5  for each k = 1,2,..., n (see picture)

So the volume of each slice is  

\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}

for k=1,2,..., n

We then add up the volumes of all these slices

\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}

Notice that the last term of the sum vanishes. After making up the expression a little, we get

\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2

But

\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)

we also know that

\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}

and

\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}

so we have, after replacing and simplifying, the sum of the slices equals

\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}

and the volume V of our solid is

\boxed{V=\displaystyle\frac{125\pi}{12}}

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Answer:

The monopolist's net profit function would be:

N(y)=198\,y\,-\,2.5\,y^2

Step-by-step explanation:

Recall that perfect price discrimination means that the monopolist would be able to get the maximum price that consumers are willing to pay for his products.

Therefore, if the demand curve is given by the function:

P(y)=200-2y

P stands for the price the consumers are willing to pay for the commodity and "y" stands for the quantity of units demanded at that price.

Then, the total income function (I) for the monopolist would be the product of the price the customers are willing to pay (that is function P) times the number of units that are sold at that price (y):

I(y)=y*P(y)\\I(y)=y\,(200-2y)\\I(y)= 200y-2y^2

Therefore, the net profit (N) for the monopolist would be the difference between the Income and Cost functions (Income minus Cost):

N(y)=I(y)-C(y)\\N(y)=(200\,y-2y^2)-(2y+0.5y^2)\\N(y)=198\,y\,-\,2.5\,y^2

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The first thing you do is subtract 2 from both sides to move the 2 to the left side
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Step-by-step explanation:

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