1 rational solution
4x² + 12x + 9 = 0
(2x+3)²=0
2x + 3 =0
2x +3 -3 = 0-3
2x = -3
2x/x = -3/2
x = -3/2
<span>You have:
- The diameter of the cylinder is 12 inches and its height is 14 inches.
-The height of the cone is 6 inches.
So, you must apply the formula for calculate the volume of the cylinder a the formula for calculate the volume of a cone.
V1=</span>πr²h
<span>
V1 is the volume of the cylinder.
r is the radius.
h is the height (h=14 inches)
The problem gives you the diameter, but you need the radius, so you have:
r=D/2
r=12 inches/2
r=6 inches
When you substitute the values into the formula, you obtain:
V1==</span>πr²h
V1=(3.14)(6 inches)²(14 inches)
V1=1582.56 inches³<span>
The volume of the cone is:
V2=(</span>πr²h)/3
<span>
V2 is the volume of the cone.
r is the radius (r=6 inches)
h is the height of the cone (h=6 inches).
Then, you have:
</span>
V2=(πr²h)/3
V2=(3.14)(6 inches)²(6 inches)/3
V2=226.08 inches³
<span>
Therefore, </span>the volume of the cake<span> (Vt) is:
Vt=V1+V2
Vt=</span>1582.56 inches³+226.08 inches³
<span> Vt=1808.6 inches</span>³
5pi/6 r^2 = 15pi
R^2 = 18
R= 3sqrt(3)
Answer:
5.5
Step-by-step explanation:
The y-intercept of the line graph shown above is the value of the point where the line cuts the y-axis. The y-intercept of this graph is between 5 and 6. However, we can get an accurate value by calculation. This can be done by generating an equation of the line.
Recall the slope-intercept equation, 
, where m = slope of the line, b = y-intercept.
To generate the equation of the line, first find slope using the points (-2, 7) and (6, 1):
.
Substitute m = ¾ and the coordinates (6, 1) into the slope-intercept equation to find the y-intercept (b):
Therefore, b = y-intercept = 5.5.
To generate the equation of the line, plug in the values of m and b, we would have:
y = ¾x + 5.5
The y-intercept of the line of the graph is 5.5.
Answer:
See graph in attachment.
Step-by-step explanation:
The graph of 
is a parabola that has its vertex at the origin.
The equation of the transformed graph is
The vertex of this transformed function is
Drag the blue graph up so that the vertex will now be at (4,3).
See graph in attachment.
