Help please!!!llalslsnsnsnsn

Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how

astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was <u>$95,300</u>.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be $x.$

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

$x=A\times (1+\frac{r}{100})^{11}$

$x=75000\times (1+\frac{2.2}{100})^{11}$

$x=75000\times (1+0.022)^{11}$

$x=75000\times (1.022)^{11}$

$x=75000\times 1.2704$

$x=95280.$

<em>The amount of house after eleven years to the nearest hundred dollars is $95,300.</em>

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0

3 years ago

What set notation best describes the range of the function graphed below ?

maxonik [38]

Answer:

I need a pic of the graph pleas3

Step-by-step explanation:

Dont mind this

7 0

1 year ago

A standard fair die is rolled one time. What is the probability that it lands on a

VLD [36.1K]

Answer:

The die is assumed to have six sides labeled

1

,

2

,

3

,

4

,

5

,

6

The numbers greater than 5 are

6

.

The numbers less than 3 are

2

,

1

.

So the numbers greater than 5 OR less than 3 are the union of the two sets or 6, and 2,1. The probability of rolling one of these numbers is

3

6

=

1

2

or

50%

.

Step-by-step explanation:

Sorry its sloppy

8 0

2 years ago

In Relation to my last question

likoan [24]

You could not use as much as your using or save more to have more.
They would be more down and not as high
3,450

7 0

3 years ago

The Boffo Product Company sells a waffle iron on which they have done product testing. They have determined that the amount of t

den301095 [7]

Answer:

They should warranty the product for 7 years if they want no more than 6.7% of the waffle irons to fail within that time.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The average waffle iron lasts for 12 years and one standard deviation is 8 months.

Measuring the time in months, we have that $\mu = 12*8 = 96$ and $\sigma = 8$