Question

What is the equation of the line that passes through the points (-3,2) and (-5,8)

Answer 1

Answer:

y = -3x - 7

Step-by-step explanation:

Slope = (8 - 2)/(-5 + 3) = 6/-2 = -3

Equation

y - 2 = - 3(x + 3)

y - 2 = -3x - 9

y = -3x - 7

Answer 2

Answer

y=-3x-7

is the equation of line that passes through the points (-3,2) and (-5,8)

step by step explanation:

we are given

(x1,y1)=(-3,2)

(x2,y2)=(-5,8)

formula of slope

m=(y2-y1 )/ (x2-x1)

putting value in formula

m=(8-2) /-5-(-3)

m=6/-5+3

m=6/-2

m=-3

Formula of line slop form of equation is

y-y1=m(x-x1)

putting the values in the formula

y-2= -3(x-(-3))

y-2= -3(x+3)

y-2=-3x-9

y=-3x-9+2

y=-3x-7

is the equation of line that passes through the points (-3,2) and (-5,8)