Answer:
i think its set B..........
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
First you need to make both bases the same:
Lets remove the ^p and ^4
To make the base of 42 equal to 41, you would have 41^x = 41
X - ln(42) / ln(41) = 1.00648904
Now you have 41^1.00648904(p) = 41^4
Now the bases are equal so we need to set the exponents to equal:
1.00648904(p) = 4
Divide both sides by 1.00648904 to solve for P
P = 4 / 1.00648904
P = 3.97421114
Answer:
see below
Step-by-step explanation:
1) Slope from P to Q is F/E
2) Definition of slope
3) F'/E' = F/E
