Answer:
170
Step-by-step explanation:
Ann, Ben, and Cindy were eating strawberries.
The ratio of the numbers of berries they ate is 5:5:7.
If Cindy ate 30 strawberries less than Ann and Ben together,
find:
what is the total number of strawberries the three of them ate?
solution:
add the ratios 5 + 5 + 7 = 17
since Cindy ate 30, less than Ann and Ben together so, the equation is
7x = 5x + 5x - 30
7x - 10x = -30
x = 30/3
x = 10
ann 5 x 10 = 50
ben 5 x 10 = 50
cindy 7 x 10 = 70
total = 170
Answer:
The fraction of tiles that will be the color of "sand" is 23/60
Step-by-step explanation:
we know that
The sum of the fractions of the tiles must be equal to 1
Let
x ----> the fraction of tiles that will be the color of "sand"
we have that
solve for x
Find the Least Common Multiple of denominators
Multiply both sides by 60
simplify
therefore
The fraction of tiles that will be the color of "sand" is 23/60
Answer:
Step-by-step explanation:
Given:
325 pages
90,000 words
Recommended reading: 200 words/ 1 minute
How many words on each page ?
90,000 words /325 pages ≈ 277 words / 1 page
Now see the picture.
The numbers for the difference I round them to the nearest word.
Answer: - 2/5
Step-by-step explanation: Isolate the vcariable by divding each side by factors that don't contain the variable.
Exact Form: x = - 2/5
Deciaml form: x = -0.4
Hope this helps! :) ~Zane
9514 1404 393
Answer:
- rewrite: 2x^2 +5x +20x +50
- factored: (x +10)(2x +5)
Step-by-step explanation:
I find this approach the most straightforward of the various ways that trinomial factoring is explained or diagramed.
You want two factors of "ac" that have a total of "b". Here, that means you want factors of 2·50 = 100 that have a total of 25. It is helpful to know your times tables.
100 = 1·100 = 2·50 = 4·25 = 5·20 = 10·10
The sums of these factor pairs are 101, 52, 29, 25, and 20. We want the pair with a sum of 25, so that's 5 and 20.
The trinomial can be rewritten using these factors as ...
2x^2 +5x +20x +50
Then it can be factored by grouping consecutive pairs:
(2x^2 +5x) +(20x +50) = x(2x +5) +10(2x +5) = (x +10)(2x +5)
_____
<em>Additional comment</em>
It doesn't matter which of the factors of the pair you write first. If our rewrite were ...
2x^2 +20x +5x +50
Then the grouping and factoring would be (2x^2 +20x) +(5x +50)
= 2x(x +10) +5(x +10) = (2x +5)(x +10) . . . . . same factoring
