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ratelena [41]
3 years ago
9

Mary is painting pumpkins to earn money. She plans on selling each pumpkin for $7.50. She currently has $200 in her savings acco

unt. Is the amount of money in her bank account proportional to the number of pumpkin she sells?
Mathematics
1 answer:
bixtya [17]3 years ago
7 0

Answer: No. It's not proportional

Step-by-step explanation:

The direct proportion in mathematics is expressed as:

y = kx

where

y = $200

k = constant

x = $7.50

We then solve for k

y = kx

200 = 7.50k

k = 200/7.50

k = 26.67

Since k isn't a whole number, then the amount of money in her bank account proportional to the number of pumpkin she sells.

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The 4 fifth-grade classrooms have a total of 29 boxes of expo markers. If the boxes are
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Answer: 7 Boxes

Step-by-step explanation:

There are 4 classrooms and 29 boxes of markers. So, you would divide 29 by 4 which is 7.25. Then, you need to round it because you don't have a quarter of a box. So, each classroom will get 7 boxes.

I hope that helps!

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3 years ago
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Below are the times (in days) it takes for a sample of 6 customers from Sarah's computer store to pay their invoices.
icang [17]

Answer:

8.80

Step-by-step explanation:

(S. D.)^2=summation(x-mean)^2/(n-1)

S. D.=sqrt(388/5)

S. D.=8.80

3 0
3 years ago
What is the sum of three consecutive even numbers is 30?
kykrilka [37]
8, 10, 12

A helpful equation:
x+x+1+x+2 = 30

Combine like terms
3x + 3 = 30

Subtract 3 from each side
3x = 27

Divide each side by to isolate x
x = 9

x = 9. However, 9 is not an even number. Let’s subtract 1 from 9 to get the first even number.

The first number is 8. The best two even numbers after 8 are 10 and 12.

8 + 10 + 12 = 30, thus this is the sequence.
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2 years ago
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If X = 4 units, Y = 3 units, and Z = 10 units, then what is the volume of the triangular pyramid shown above?
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5 0
2 years ago
Lagrange multipliers have a definite meaning in load balancing for electric network problems. Consider the generators that can o
Ivahew [28]

Answer:

The load balance (x_1,x_2,x_3)=(545.5,272.7,181.8) Mw minimizes the total cost

Step-by-step explanation:

<u>Optimizing With Lagrange Multipliers</u>

When a multivariable function f is to be maximized or minimized, the Lagrange multipliers method is a pretty common and easy tool to apply when the restrictions are in the form of equalities.

Consider three generators that can output xi megawatts, with i ranging from 1 to 3. The set of unknown variables is x1, x2, x3.

The cost of each generator is given by the formula

\displaystyle C_i=3x_i+\frac{i}{40}x_i^2

It means the cost for each generator is expanded as

\displaystyle C_1=3x_1+\frac{1}{40}x_1^2

\displaystyle C_2=3x_2+\frac{2}{40}x_2^2

\displaystyle C_3=3x_3+\frac{3}{40}x_3^2

The total cost of production is

\displaystyle C(x_1,x_2,x_3)=3x_1+\frac{1}{40}x_1^2+3x_2+\frac{2}{40}x_2^2+3x_3+\frac{3}{40}x_3^2

Simplifying and rearranging, we have the objective function to minimize:

\displaystyle C(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)

The restriction can be modeled as a function g(x)=0:

g: x_1+x_2+x_3=1000

Or

g(x_1,x_2,x_3)= x_1+x_2+x_3-1000

We now construct the auxiliary function

f(x_1,x_2,x_3)=C(x_1,x_2,x_3)-\lambda g(x_1,x_2,x_3)

\displaystyle f(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)-\lambda (x_1+x_2+x_3-1000)

We find all the partial derivatives of f and equate them to 0

\displaystyle f_{x1}=3+\frac{2}{40}x_1-\lambda=0

\displaystyle f_{x2}=3+\frac{4}{40}x_2-\lambda=0

\displaystyle f_{x3}=3+\frac{6}{40}x_3-\lambda=0

f_\lambda=x_1+x_2+x_3-1000=0

Solving for \lambda in the three first equations, we have

\displaystyle \lambda=3+\frac{2}{40}x_1

\displaystyle \lambda=3+\frac{4}{40}x_2

\displaystyle \lambda=3+\frac{6}{40}x_3

Equating them, we find:

x_1=3x_3

\displaystyle x_2=\frac{3}{2}x_3

Replacing into the restriction (or the fourth derivative)

x_1+x_2+x_3-1000=0

\displaystyle 3x_3+\frac{3}{2}x_3+x_3-1000=0

\displaystyle \frac{11}{2}x_3=1000

x_3=181.8\ MW

And also

x_1=545.5\ MW

x_2=272.7\ MW

The load balance (x_1,x_2,x_3)=(545.5,272.7,181.8) Mw minimizes the total cost

5 0
3 years ago
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