Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Answer:
-1, 2, 6
Step-by-step explanation:
We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).
Now, we have, 
⇒
⇒
⇒
⇒![(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0](https://tex.z-dn.net/?f=%28x-2%29%28x-6%29%5B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20-5x-2%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5D%3D0)
⇒ 
or, ![[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20-5x-2%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5D%3D0)
If, (x-2)(x-6) =0, then x=2 or x=6
If, , then 
and (x-6)(x+1) =0
Therefore, x=6 or -1
So the solutions for x are -1, 2 6. (Answer)
Answer:
16
10
160
Step-by-step explanation:
The base also known as the right space is 16 because its labeled!
The height is also Labeled as 10.
Now all you have to do is 10 x 16 which equals 160!
Sorry I'm late!
Y=mx+b
m=slope
the greater m is the steeper the graph
so the correct answer is B
Answer:
any # where -2<=x<7
Step-by-step explanation:
(x-7) would be negative and (x+3) positive, resulting in f(x) being negative.
