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aliya0001 [1]
3 years ago
6

Evaluate 3/2y-3+5/3z when y =6 and z =3

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0

pluge in

3/2*6-3+5/3*3

1/4-3+5/6

3/12+10/12-3

13/12+3

4.083333

satela [25.4K]3 years ago
5 0

Answer:

The result is 11

Step-by-step explanation:

For solving the problem, we must replace the values of y and z into the expression, then we must apply the corresponding operators such as addition, subtraction, division and multiplication. It is assumed that the expression is as follows:

\frac{3}{2}y-3+\frac{5}{3}z

If we replace the values of y and z, we get:

\frac{3}{2}\cdot 6-3+\frac{5}{3}\cdot 3

The first term \frac{3}{2}\cdot 6 equals 9

The second term is 3

The third term \frac{5}{3}\cdot 3 equals 5

The expression would be:

9-3+5=11

The result of the expression is 11

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Triangle A"B"C" are similar triangles to triangle ABC and all corresponding angles are congruent. Also, triangle A"B"C" is twice the size of triangle ABC.

<h3>What is transformation?</h3>

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Hence:

Triangle A"B"C" are similar triangles to triangle ABC and all corresponding angles are congruent. Also, triangle A"B"C" is twice the size of triangle ABC.

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8 0
2 years ago
Every third visitors to a museum gets a free bumper sticker. Every fifth visitor to that museum gets a free key chain. Which vis
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The fifteenth customer will be the first because 5x3=15

8 0
3 years ago
A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud
iris [78.8K]

Answer:

-0.048

Do not reject  H_0:P_1-P_2=0

Step-by-step explanation:

From the question we are told that

Sample size n_1=350

Sample size n_2=250

Sample proportion 1  \hat P= \frac{25}{350} =>0.07

Sample proportion 2 \hat P= \frac{19}{250} =>0.076

95% confidence interval

Generally for 95% confidence level

Level of significance

 \alpha = 1-0.95=>0.05

 \alpha /2=\frac{0.05}{2} =>0.025

Therefore

Z_a_/_2=1.96

Generally the equation for confidence interval between P_1 - P_2  is mathematically given as

(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2}  }

(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250}  }

(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4  }

(-0.006)\pm 0.042

(-0.006)- 0.042=>-0.048

(-0.006)+ 0.042=>0.036

Therefore

Confidence interval is

-0.048

Conclusion

Given the confidence interval has zero

Therefore do not reject  H_0:P_1-P_2=0

6 0
2 years ago
After a snowstorm in the town of Golden Glen, the morning temperature was – 10°F. But by the afternoon, the temperature had rise
spayn [35]

Answer:

7°F

Step-by-step explanation:

We have the following information from the question;

Morning temperature = -10°F

Increase in temperate = 17°F

Afternoon temperature = the unknown

Since;

Increase in temperature = Afternoon temperature - morning temperature

Then;

Afternoon temperature = increase in temperature + morning temperature

Afternoon temperature = 17°F + (-10°F)

Afternoon temperature= 7°F

5 0
3 years ago
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