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3 years ago

Find the slope write into slope intercept form (19,-16),(-7,-15)

Mathematics

2 answers:

avanturin [10]3 years ago

6 0

Answer: $m= -\frac{1}{26}$

(19,-16) = (x1,y1)

(-7-15) = (x2,y2)

Slope= $\frac{y2-y1}{x2-x1}$

= $\frac{-15-(-16)}{-7-19}$

= $\frac{-15+16}{-7-19}$

= $\frac{-15+16}{-26}$

= $-\frac{1}{26}$

lesya [120]3 years ago

3 0

The slope is 1/-26 so y+16=1/-26(x-19)

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Finds the slope of the line

Zinaida [17]

Answer:

Step-by-step explanation:

Slope=rise over run.

From bottom marked point (-3, -3) to the other (-2, 1)...

Rise= 4

Run= 1

4/1=4

Therefore, the slope is 4.

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2 years ago

Find a linear equation whose graph is the straight line with the given property.

Triss [41]

Answer:

Step-by-step explanation:

-5.25+2.25 - 3

1-0.5 = 0.5

=-6 =m

y=-6x

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2 years ago

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g. How many of each weight is needed?

Delicious77 [7]

The required number of weights used in chemical balance to weigh 237g is 4,1,1,7 respectively.

What is mathematical expression?

A mathematical expression expression in mathematical is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Here, it is given that :

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g.

Now, let us find the number of weights for each weight type :

For 50g weight the maximum number of weights needed will be 4 that is :

50g x 4 = 200g

Now, for 20g weight the maximum number of weights needed will be 1 that is :

20g x 1 = 20g

Now, for 10g weight the maximum number of weights needed will be 1 that is :

10g x 1 = 10g

Now, for 1g weight the maximum number of weights needed will be 7 that is :

1g x 7 = 7g

Adding all the weights we get :

200g + 20g + 10g + 7g = 237g;

which is the required weight and the number of weights used is 4,1,1,7 respectively.

Read more about weights at:

brainly.com/question/16177712

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4 0

1 year ago

Read 2 more answers

Use the Triangle Inequality Property to determine whether a triangle can be formed with the given side lengths. 4 m, 8 m, 9 m *

Illusion [34]

Answer:

Therefore a triangle can be formed with side lengths of 4 m, 8 m, 9 m

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene, isosceles, equilateral and so on.

The triangle inequality property states that the sum of any two sides of a triangle must be greater than the third side. If a, b and c are the sides of a triangle then:

a + b > c; a + c > b; b + c > a

Given a triangle with side length 4 m, 8 m, 9 m:

4m + 8m = 12m > 9m

4m + 9m = 13m > 8m

8m + 9m = 17m > 4m

Therefore a triangle can be formed with side lengths of 4 m, 8 m, 9 m.

7 0

2 years ago

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

<u>Addition: </u>

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

<u>Multiplication: </u>

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

8 0

3 years ago